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Juli2301 [7.4K]
2 years ago
12

Marisela cut four equivalent lengths of ribbon. Each was 5 eighths of a yard long. How many yards of ribbon did she cut? Express

your answer as the sum of a whole number and the remaining fractional units. Draw a number line to represent the problem.

Mathematics
1 answer:
kakasveta [241]2 years ago
7 0

Answer:

2\frac{1}{2} yards.

Step-by-step explanation:

Please find the attachment.  

We have been given that Marisela cut four equivalent lengths of ribbon. Each was 5 eighths of a yard long.    

To find yards of ribbon cut by Marisela, we will multiply 4 by 5 eighths of a yard (5/8).

\text{Total ribbon cut by Marisela}=4\times \frac{5}{8}

\text{Total ribbon cut by Marisela}=\frac{4\times 5}{8}

\text{Total ribbon cut by Marisela}=\frac{20}{8}

Express answer as the sum of whole number and the remaining fractional units:

\text{Total ribbon cut by Marisela}=\frac{16+4}{8}

\text{Total ribbon cut by Marisela}=\frac{16}{8}+\frac{4}{8}

\text{Total ribbon cut by Marisela}=2+\frac{4}{8}

\text{Total ribbon cut by Marisela}=2\frac{4}{8}

Therefore, Marisela cut 2\frac{4}{8} yards of ribbon.  

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One way to measure whether the trees in the Wade Tract are uniformly distributed is to examine the average location in the north
tatyana61 [14]

Answer:

Null hypothesis be H₀ : μ = 100

Alternative hypothesis Hₐ : μ < 100

There is sufficient statistical evidence to suggest that the average location of Wade Tract is 100

Step-by-step explanation:

Here we have;

Let our null hypothesis be H₀ : μ = 100 Average location of trees in the Wade Tract is 100

Our alternative hypothesis becomes Hₐ : μ < 100 at 95% confidence level

Proposed average location in Wade Tract, μ = 100

Sample mean, \bar x = 99.74

Standard deviation, s = 58

Sample size, n = 584

The t test formula is therefore;

t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}}

Therefore, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025

We have t_{\alpha /2} = -1.65

Plugging in the values into the t test formula, we have t = -0.108338, from which the p-value is given as p = 0.4569 which is much more than the value of α, therefore, we accept the null hypothesis as follows;

There is sufficient statistical evidence to suggest that the average location of Wade Tract = 100.

7 0
2 years ago
Add.
Leya [2.2K]

The answer is 6.4

It is positive because the 11.4 is larger than the negatvie 5.

I hope this helps!

8 0
2 years ago
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A fishing club on the Restigouche River in Canada kept detailed records on the numbers of fish caught by its members between 188
MrMuchimi

Answer:a

Step-by-step explanation:

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2 years ago
A rectangle has an area of 256 cm 2 . it has a width that is 48 cm shorter than 4 times its length. what is the rectangle's leng
AveGali [126]
Let
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width

we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1

y=4x-48------> y=4x-48------> equation 2

substitute equation 2 in equation 1

256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using  a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm

is a square

the answer is
</span>the rectangle's length is 16 cm

8 0
2 years ago
Which expression is equivalent to StartFraction (5 a b) cubed Over 30 a Superscript negative 6 Baseline b Superscript negative 7
lorasvet [3.4K]

Answer: \frac{25}{6} a^{9} b^{10}

Step-by-step explanation:

Assuming the described expression is:

\frac{(5ab)^{3}}{30 a^{-6} b^{-7}}

And knowing the condition a \neq 0 and b \neq 0

We cansimplify it following the rules related to the exponents with the same base:

\frac{25}{6} a^{3} b^{3} a^{6} b^{7}

Finally:

\frac{25}{6} a^{9} b^{10}

3 0
2 years ago
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