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qwelly [4]
2 years ago
7

How could Brent use a rectangle to model the factors of \large x^2-7x+6?

Mathematics
1 answer:
Bad White [126]2 years ago
5 0

Answer:He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.

Step-by-step explanation:

He could draw a diagram of a rectangle with dimensions x – 1 and x – 6 and then show the area is equivalent to the sum of x2, –x, –6x, and 6.

He could draw a diagram of a rectangle with dimensions x + 7 and x – 1 and then show the area is equivalent to the sum of x2, 7x, –x, and 6.

He could draw a diagram of a rectangle with dimensions x – 3 and x – 4 and then show the area is equivalent to the sum of x2, –3x, –4x, and half of 12.

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A tape manufacturer reduces the price of its heavy duty tape from $30 to $28 a reel, and the price of regular tape from $20 to $
juin [17]
3/5 of 1600 = $960 spent for heavy duty tapes
1600 - 960 = $640 spent for regular tapes

The company normally bought 
960 ÷ 30 = 32 heavy duty tapes
640 ÷ 20 = 32 regular tapes

With the new prices, the company is paying 
32 × 28 = 896 for the heavy duty tapes
32 × 19 = 608 for the regular tapes

The company is saving
960 - 896 = $64 for the heavy duty tapes
640 - 608  = $32 for the regular tapes

4 0
2 years ago
the area of a rectangular field is 18000m^2 if the ratio of length and breath is 5:4 find its perimeter
zavuch27 [327]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{540 \: m}}}}}

Step-by-step explanation:

Let the length and breadth be 5x and 4x respectively.

Area of rectangular field = 18000 m²

<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x</u>

Area of rectangle = \sf{l \times b}

Plug the values

⇒\sf{18000 = 5x \times 4x}

Calculate the product

⇒\sf{18000 = 20 {x}^{2} }

Swap the sides of the equation

⇒\sf{20 {x}^{2}  = 18000}

Divide both sides of the equation by 20

⇒\sf{ \frac{20 {x}^{2} }{20}  =  \frac{18000}{20} }

Calculate

⇒\sf{ {x}^{2}  = 900}

Squaring on both sides

⇒\sf{x = 30}

<u>Replacing the value of x in order to find the value of length and breadth</u>

Length = \sf{5x = 5 \times 30 = 150 \: m}

Breadth = \sf{4x = 4 \times 30 = 120 \: m}

<u>Finding </u><u>the </u><u>perimeter</u><u> </u><u>of </u><u>the </u><u>rectangular</u><u> </u><u>field</u>

Perimeter of rectangle = \sf{2(l + b)}

plug the values

⇒\sf{2(150 + 120)}

Distribute 2 through the parentheses

⇒\sf{300 + 240}

Add the numbers

⇒\sf{540 \: m}

Hope I helped !

Best regards!!

8 0
2 years ago
According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 9x^4 – 2x^2 – 3x + 4?
julia-pushkina [17]

Answer: \pm1,\frac{\pm1}{3},\frac{\pm1}{9},\pm2,\frac{\pm2}{3},\frac{\pm2}{9},\pm4,\frac{\pm4}{3},\frac{\pm4}{9}


Step-by-step explanation:

The rational theorem states that if f(x) has integer coefficients and \frac{p}{q} is a rational zero, then q is the factor of leading coefficient and p is the factor of constant term.

Given polynomial= 9x^4-2x^2-3x+4

Now, Factors of leading coefficient q=\pm9,\pm3,\pm1

factors of constant term p=\pm4,\pm2,\pm1

according to rational root theorem the rational roots are in the form

\frac{p}{q}=\pm1,\frac{\pm1}{3},\frac{\pm1}{9},\pm2,\frac{\pm2}{3},\frac{\pm2}{9},\pm4,\frac{\pm4}{3},\frac{\pm4}{9}

5 0
2 years ago
Read 2 more answers
Complete the steps to find all zeroes of the function f(x) = x4 − 4x3 − 4x2 + 36x − 45. This function has roots.
xxTIMURxx [149]
Steps?

A graph shows zeros to be ±3. Factoring those out leaves the quadratic
  (x-2)² +1
which has complex roots 2±i.

The function has roots -3, 3, 2-i, 2+i.

7 0
2 years ago
Read 2 more answers
1 kilogram is equivalent to about 2.2 pounds. An orangutan weighs 142 pounds. What is its mass in kilograms? Round your answer t
snow_lady [41]

The mass of orangutan is 64.5 kilograms

<em><u>Solution:</u></em>

Given that orangutan weighs 142 pounds

Also given that,

1 kilogram is equivalent to about 2.2 pounds

Now let us convert 142 pounds to kilograms

1 kilogram = 2.2 pounds

\text{1 pound } = \frac{1}{2.2} \text{ kilograms }

Therefore, 142 pounds is equivalent to,

142 \text{ pound } = \frac{1}{2.2} \times 142 \text{ kilogrmas }

\rightarrow \frac{1}{2.2} \times 142 = 64.545 \text{ kilograms }

On rounding to nearest tenth we get, 64.5 kilograms

Thus mass of orangutan is 64.5 kilograms

3 0
2 years ago
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