Answer: H is the correct answer
Step-by-step explanation:
First, Kendra deposited $78 into her savings. Then, she added $50 more which is 128. She withdraw $27 and was left with $101
Answer:

Step-by-step explanation:
step 1
Find the area of complete circle
The area of the circle is given by the formula

we have

substitute


step 2
Find the area of the shaded region
we know that
The area of complete circle subtends a central angle of 360 degrees
so
using proportion
Find out the area of the shaded region if the central angle is equal to 80 degrees

Answer: He should have translated the scenario as value of all dimes = value of all
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 175cm
Standard deviation = 6 cm
Percentage of students below 163 cm
163 = 175 - 2*6
So 163 is two standard deviations below the mean.
By the Empirical rule, 95% of the heights are within 2 standard deviations of the mean. The other 100-95 = 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of them are more than 2 standard deviations below the mean(so below 163cm) and 2.5% are more than two standard deviations above the mean.
2.5% of the students have heights less than 163cm.
Out of 1000
0.025*1000 = 25
25 is the answer
Answer:
The probability that they are both male is 0.424 (3 d.p.)
Step-by-step explanation:
The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter
Prob (1st male) = 8 ÷ 12 = 0.667
Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.
Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636
Therefore,
Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424