Suki makes and sells denim jackets in a small store at the mall. She has found that

What are the zeros of the quadratic function f(x) = 6x^2 + 12x – 7?

strojnjashka [21]

Answer:

$x1=\frac{-2+\sqrt{26/3}}{2}$

$x2=\frac{-2-\sqrt{26/3} }{2}$

Step-by-step explanation:

To find the zeros of the quadratic function f(x)=6x^2 + 12x – 7 we need to factorize the polynomial.

To do so, we need to use the quadratic formula, which states that the solution to any equation of the form ax^2 + bx + c = 0 is:

$x=\frac{-b±\sqrt{b^{2}-4ac}}{2a}$

So, the first thing we're going to do is divide the whole function by 6:

6x^2 + 12x – 7 = 0 -> x^2 + 2x - 7/6

This step is optional, but it makes things quite easier.

Then we using the quadratic formula, where:

a=1, b= 2, c = -7/6.

Then:

$x=\frac{-2±\sqrt{2^{2}-4(1)(-7/6)}}{2}$

$x=\frac{-2±\sqrt{4 +14/3}}{2}$

$x=\frac{-2±\sqrt{26/3}}{2}$

So the zeros are:

$x1=\frac{-2+\sqrt{26/3}}{2}$

$x2=\frac{-2-\sqrt{26/3}}{2}$

4 0

2 years ago

Most states categorize possession of cocaine charges by weight. Possessing less than a gram will result in the lowest level of f

AleksAgata [21]

Answer:

Over 2 oz. Class A-II felony

Step-by-step explanation:

One would need to carefully weigh the material.*

0.06 kg ≈ 2.12 oz

Note that .06 kg is 1 significant figure, so this rounds to 2 oz (1 significant figure). Given the precision of the reported weight, there is insufficient precision to say the amount is actually over 2 oz.

__

If you take the numbers at face value, the suspect is in possession of over 2 oz, so will be charged with a Class A-II felony.

_____

* 2.00 ounces translates to about 0.0567 kg, which rounds to 0.06 kg.

3 0

2 years ago

Which of the following rational functions is graphed below?

AlekseyPX

Answer:

The rational function that is graphed is B

6 0

2 years ago

Read 2 more answers

Unless otherwise specified, the domain of a function f is assumed to be the set of all real numbers x for which f(x) is a real n

e-lub [12.9K]

Answer:

See Below

Step-by-step explanation:

The function is a piecewise function defined as:

$N(t)=\left \{ {{25t+150} \ 0 \leq t \leq 6 \atop {\frac{200+80t}{2+0.05t} \ t \geq 8}} \right.$

a)

We need to find the limit of the function as t goes to infinity. This means what is the max value of fish in the pond given times goes to infinity (on an on).

We will take the 2nd part of the equation since t falls into that range, t is infinity, which is definitely greater than 8.

$\lim_{t \to \infty} \frac{200+80t}{2+0.05t} \\\lim_{n \to \infty} \frac{80t}{0.05t}\\ \lim_{n \to \infty} \frac{80}{0.05} =1600$

This means the maximum number of fish at this pond is 1600, no matter how long it goes on.

b)

A function is continuous at a point if we have the limit and the functional value at that point same.

Functional value at t = 8 is (we use 2nd part of equation):

$\frac{200+80t}{2+0.05t}\\\frac{200+80(8)}{2+0.05(8)}\\=350$

We do have a value and limit also goes to this as t approaches 8.

So, function is continuous at t = 8

c)

We want to find is there a "time" when the number of fishes in the pond is 250, during t from 0 to 6. We plug in 250 into N(t) and try to find t. Make sure to use the 1st part of the piece-wise function. Shown below:

$N(t)=25t+150\\250=25t+150\\25t=250-150\\25t=100\\t=4$

The time is 4 years when the number of fishes in the pond is 250

6 0

2 years ago

Connor has seven more nickels than dimes and twice as many quarters as dimes. If he has $6.20, how many nickels does he have?

Novosadov [1.4K]

Connor has 16 nickels. If you have 9 dimes (90 cents) and you doubled it that would give you 18 quarters ($4.50). you have 7 more nickels than dimes, so you do 7+9 which equals 16 nickels (80 cents). 90+450+80=620.

8 0

2 years ago