All categories

1 year ago

Alycia and her 4 friends share 3 pizzas equally. How much of one pizza does each person get?

Mathematics

2 answers:

alina1380 [7]1 year ago

7 0

Each person will get 1/4 of one pizza

explanation(sorry if it’s confusing)-

miv72 [106K]1 year ago

5 0

3/5 of the pizza counting Alycia + her 4 friends.

You might be interested in

Liam is constructing a square in which two of its vertices are points A and B. He has already used his straightedge and compass

AfilCa [17]

Answer:

Step-by-step explanation:

3 0

2 years ago

Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp

yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

$H_0: \mu=2\\\\H_a:\mu< 2$

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803$

The degrees of freedom for this sample size are:

$df=n-1=52-1=51$

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0

2 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

adoni [48]

Step-by-step explanation

<h3>Prerequisites:</h3>

$b^2 - 4ac = 0 \Rightarrow 1 solution$

$b^2 - 4ac > 0 \Rightarrow 2 solutions$

$b^2 - 4ac < 0 \Rightarrow No\ real\ solutions$

----------------------------------------------------------------

$2x^2-7x-9 = 0$

$b^2 - 4ac$

$-7^2 - 4(2)(-9) = 121$

2 Solutions

---------------------------------------------------------------

$x^2-4x+4 = 0$

$b^2 - 4ac$

$-4^2 - 4(1)(4) = 0$

1 Solution

---------------------------------------------------------------

$4x^2-3x-1 = 0$

$b^2 - 4ac$

$-3^2 - 4(4)(-1) = 25$

2 Solutions

---------------------------------------------------------------

$x^2-2x-8 = 0$

$b^2 - 4ac$

$-2^2 - 4(1)(-8) = 36$

2 Solutions

---------------------------------------------------------------

$3x^2+5x+3 = 0$

$b^2 - 4ac$

$5^2 - 4(3)(3) = -11$

No Solutions

---------------------------------------------------------------

3 0

2 years ago

Read 2 more answers

The number w and 0.8 are additive inverses.

umka2103 [35]

Since, the number w and 0.8 are additive inverses.

A number 'a' is said to have an additive inverse '-a' if "a+ (-a)= 0".

Since, 'w' and '0.8' are additive inverses of each other such that $w + 0.8 = 0$

Therefore, the value of 'w' should be '-0.8' so that $-0.8 + 0.8 = 0$ .

So, the value of 'w' is =0.8

Now, Refer to the attached image which represents the position of 0.8 , w ( that is -0.8) and the sum of 0.8 and w.

Sum of 0.8 and w = 0.8 + w

= 0.8 +(-0.8)

= 0.

3 0

2 years ago

Read 2 more answers

The distance d (in miles) that you can see to the horizon with your eye level h feet above the water is given by d=3h2−−−√. You

liubo4ka [24]

Answer: He cannot see a ship that is 4.5 miles away.

Step-by-step explanation:

Since we have given that

$d=3\sqrt{h}$

Here, h is the eye level above the water

d is the distance away.

If h = 12 feet

We will get :

$d=3\sqrt{12}\\\\d=3\times 2\sqrt{3}\\\\d=6\sqrt{3}\\\\d=10.39$

Hence, it is 10.39 feet away when eye level is 12 feet above the water.

Therefore , he cannot see a ship that is 4.5 miles away.

7 0

2 years ago