Alycia and her 4 friends share 3 pizzas equally. How much of one pizza does each person get?
2 answers:
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Note necessary facts about isosceles triangle ABC:
- The median CD drawn to the base AB is also an altitude to tha base in isosceles triangle (CD⊥AB). This gives you that triangles ACD and BCD are congruent right triangles with hypotenuses AC and BC, respectively.
- The legs AB and BC of isosceles triangle ABC are congruent, AC=BC.
- Angles at the base AB are congruent, m∠A=m∠B=30°.
1. Consider right triangle ACD. The adjacent angle to the leg AD is 30°, so the hypotenuse AC is twice the opposite leg CD to the angle A.
AC=2CD.
2. Consider right triangle BCD. The adjacent angle to the leg BD is 30°, so the hypotenuse BC is twice the opposite leg CD to the angle B.
BC=2CD.
3. Find the perimeters of triangles ACD, BCD and ABC:
4. If sum of the perimeters of △ACD and △BCD is 20 cm more than the perimeter of △ABC, then
5. Since AC=BC=2CD, then the legs AC and BC of isosceles triangles have length 20 cm.
Answer: 20 cm.
Answer:
Step-by-step explanation:
<h3> The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle andLet be "s" the total number of seats in the Stalls.
The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is .
Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:
Solving for "s", we get:
So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:
We know that of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:
Therefore, the total number of seats that were occupied las Friday is:
Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:
Solving for "p", we get: