a bicycle wheel has a diameter of 40 cm how many revolutions would a wheel make if the bike travels 1 km pi=3.14 (answer please
with working out)
1 answer:
<span>Circumference of a circle = Diameter × pi
Circumference of a circle = 40 cm × 3.14
<u>Circumference of the wheel = 125.6 cm
</u>
1 Km = 1000m
</span>Circumference of the wheel × 1000m = The number of revolutions
125.6 × 1000m = 125600
<u><em>
</em></u>The wheel would make <u>125600 revolutions</u> if the bike travels 1 km.
Circumference of a circle = 40 cm × 3.14
<u>Circumference of the wheel = 125.6 cm
</u>
1 Km = 1000m
</span>Circumference of the wheel × 1000m = The number of revolutions
125.6 × 1000m = 125600
<u><em>
</em></u>The wheel would make <u>125600 revolutions</u> if the bike travels 1 km.
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In the game of cornhole, when Sasha tossed a bean bag to the edge of the hole, in which the equations of the hole and bean bag's path are x² + y² = 5 and y = 0.5x² + 1.5x - 4, respectively, she could have tossed her bean bag to the points (1, -2) or (2, 1).
To find the points in which she could have tossed her bean bag, we need to intersect the two equations of the function as follows.
<u>The equation for the hole</u>
(1)
<u>The equation for the path of the bean bag</u>
(2)
By entering equation (2) into (1) we have:
By solving for <em>x</em>, we have:
x₁ = 1
x₂ = 2
Now, for <em>y</em> we have (eq 2):
- <u>x₁ = 1</u>
- <u>x₂ = 2</u>
Therefore, the points are (1, -2) or (2, 1).
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I hope it helps you!
Answer:
<u>Properties that are present are </u>
Property I
Property IV
Step-by-step explanation:
The function given is where b > 1
Let's take a function, for example,
Let's check the conditions:
I. As the x-values increase, the y-values increase.
Let's put some values:
y = 2 ^ 1
y = 2
and
y = 2 ^ 2
y = 4
So this is TRUE.
II. The point (1,0) exists in the table.
Let's put 1 into x and see if it gives us 0
y = 2 ^ 1
y = 2
So this is FALSE.
III. As the x-value increase, the y-value decrease.
We have already seen that as x increase, y also increase in part I.
So this is FALSE.
IV. as the x value decrease the y values decrease approaching a singular value.
THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.
This is TRUE.
Option I and Option IV are true.