Question

If the cheetah made a round-trip and took half the amount of time on the return trip as on the front end of the trip, what would be the relationship between the average rates on each leg of the trip? Using a complete sentence, explain how you arrived at this conclusion.

Answer 1

Answer:

The average rate on second leg of the trip is twice of average rate on first leg of the trip.

Step-by-step explanation:

The formula for average speed is

$Speed=\frac{Distance}{Time}$

$s=\frac{d}{t}$

$s\propto\frac{1}{t}$

It means the speed is inversely proportional to the time. If the speed increases then time deceases and if speed decrees then time increases.

It is given that the cheetah made a round-trip and took half the amount of time on the return trip as on the front end of the trip.

Let s₁ and s₂ are average speed on first and second leg respectively. t₁ is time on the first trip.

$s_1=\frac{d}{t_1}$

$s_2=\frac{d}{\frac{t_1}{2}}$

$s_2=2\frac{d}{t_1}$

$s_2=2s_1$

Therefore, the average rate on second leg of the trip is twice of average rate on first leg of the trip.