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NARA [144]
2 years ago
7

Which quantities decrease as the distance between a planet and the Sun increases? Check all that apply.

Physics
2 answers:
sweet-ann [11.9K]2 years ago
5 0

<u>Answer</u>

Gravitational force

<u>Explanation</u>

Gravitational force is the force of attraction between two bodies of a given masses. It is calculated as follows:

Gravitational force = GM₁M₂/r²

From the formula it can be seen that gravitational force is inversely proportional to the r where are is the distance between the two bodies.

When the distance increases the gravitational force decreases.

Zielflug [23.3K]2 years ago
4 0

Here’s a picture of the correct answers.

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A ball, which has a mass of 1.25 kg, is thrown straight up from the top of a building 225 meters tall with a velocity of 52.0 m/
Elena-2011 [213]

First we will find the speed of the ball just before it will hit the floor

so in order to find the speed of the cart we will first use energy conservation

KE_i + PE_i = KE_f + PE_f

\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv_f^2 + 0

\frac{1}{2}(1.25)(52)^2 + 1.25(9.8)(225) = \frac{1}{2}(1.25)v_f^2

So by solving above equation we will have

v_f = 84.3 m/s

now in order to find the momentum we can use

P = mv

P = 1.25 \times 84.3

P = 105.4 kg m/s

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2 years ago
Consider a boat heading due east at 15 miles/hour. The water's current is moving at 7.1 miles/hour at 45º south of east. Drag ve
givi [52]

If a boat is going East at 15mph and there is a water current going southeast at 45° then the boat is being drifted southward.  So since the current is going at an angle then it has a x and y component.  So Rx refers to the x-component force of the current and Ry refers to the y-component of the current, and |R| refers to the magnitude of these forces.

7 0
2 years ago
Read 2 more answers
Find an expression for the torsional constant k in terms of the moment of inertia I of the disk and the angular frequency ω of s
sasho [114]

Answer:

Explanation:

The general equation for the disk with moment of inertia I when given small angular displacement  \theta is given by

I\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=-k\theta

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}+\frac{k\theta }{I}=0

Replacing

\frac{k\theta }{I}=\omega ^2

where \omega is the angular frequency of oscillation

General solution for this Equation is given by

\theta =\theta _{max}\sin \left ( \omega t+\phi \right )

where \theta _{max}=maximum\ angular\ displacement

\phi =Phase\ difference

Thus K can be written as

k=I\omega ^2

5 0
2 years ago
Small blocks, each with mass m, are clamped at the ends and at the center of a rod of length L and negligible mass. Compute the
fenix001 [56]

Answer:

Answered

Explanation:

a) Two balls are at a distance of L/2 from the axis of rotation and one block at the center. ( center of rod).

therefore,

I=2\times m\frac{L}{2}^2

I= \frac{1}{2}mL^2

b) two balls at a distance L/4 at the from the axis and 1 ball at a distance 3L/4 from the from the axis.

I= 2\times m\times(L/4)^2 + m(\frac{3L}{4})^2

= \frac{1}{16} mL^2(2+9)= \frac{11}{16}mL^2

5 0
2 years ago
A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen
Svetllana [295]

Answer:

h_p = 30.46\ m

Explanation:

<u>Free Fall Motion</u>

A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.

The speed vf of the object when a time t has passed is given by:

v_f=g\cdot t

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Similarly, the distance y the object has traveled is calculated as follows:

\displaystyle y=\frac{g\cdot t^2}{2}

If we know the height h from which the object was dropped, we can solve the above equation for t:

\displaystyle t=\sqrt{\frac{2\cdot y}{g}}

The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:

\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec

The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:

t_2=2.56 - 2 = 0.56\ sec

Therefore, it has traveled down a distance:

\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m

Thus, the height of the pen is:

h_p = 32 - 1.54\Rightarrow h_p=30.46\ m

8 0
2 years ago
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