How many atoms of c are in 0.185 mol of (c3h5)2o?
1 answer:
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<h3>Answer:</h3>
112.08 mL
<h3>Explanation:</h3>From the question we are given;
- Initial volume, V1 = 100.0 mL
- Initial temperature, T1 = 225°C, but K = °C + 273.15
thus, T1 = 498.15 K
- Initial pressure, P1 = 1.80 atm
- Final temperature , T2 = -25°C
= 248.15 K
- Final pressure, P2 = 0.80 atm
We are required to calculate the new volume of the gases;
- According to the combined gas law equation;
Rearranging the formula;
Therefore;
Therefore, the new volume of the gas is 112.08 mL
Answer:
...1
...2
Explanation:
The ternary constant is given by the following equation:
The symbol XiXi, where XX is an extensive property of a homogeneous mixture and the subscript ii identifies a constituent species of the mixture, denotes the partial molar quantity of species ii defined by
This is the rate at which property X changes with the amount of species i added to the mixture as the temperature, the pressure, and the amounts of all other species are kept constant. A partial molar quantity is an intensive state function. Its value depends on the temperature, pressure, and composition of the mixture.
In a multi phase system (in this case, a ternary system), the components resolved give:
and