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Natasha2012 [34]
2 years ago
15

There are 3 times elephants compared to giraffes in the safari. If there is a total of 88 elephants and giraffes,how many elepha

nts are there in the safari?
Mathematics
1 answer:
77julia77 [94]2 years ago
5 0
There are 66 elephants in the safari. 

Solution:
The number 88 refers to both elephants and giraffes that are in the safari. We know that the number of elephants is thrice the number of giraffes. So we can let x be the number of giraffes and 3x be the number of elephants. 

We will then come up with the following equation:
3x + x = 88

Then, just add the two variables, and continue the operation.
4x = 88
x = 88/4
x = 22

Now we know that there are 22 giraffes in the safari. So 3x, or 3(22) = 66. There are 66 elephants in the safari.
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Angela has the following coins in her pocket:
GaryK [48]

Answer:

  • There are 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

Explanation:

The possible combinations are:

1. Assuming the first coin is 10p:

  • (10p, 1p)
  • (10p, 50p)
  • (10p, 2p)
  • (10p, 20p)

2. Asuming the first coin is 1p

Do not count (1p, 10p) as it is the same combination as (10p, 1p)

  • (1p, 50p)
  • (1p, 2p)
  • (1p, 20p)

3. Assuming the first coin is 50p:

Do not count (50p, 10p) nor (50p, 1p) as they are the same combinations (10p, 50p) and (1p, 50p) counted earlier:

  • (50p, 2p)
  • (50p, 20p)

4. Assuming the first coin is 2p:

The only new combination is:

  • (2p, 20p)

5. All the combinations with 20p have already been listed.

Therefore:

  • There are 4 + 3 + 2 + 1 = 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

7 0
2 years ago
There are 9 students in a service club. The club is making gift baskets for children in a hospital. Each club member donated 4 c
VladimirAG [237]

Answer:

Step-by-step explanation:

Let x represent the number of toys that each club member donated.

There are 9 students in a service club.

If each club member donated 4 children's books for the baskets, it means that the total number of books donated by the club members would be

9 × 4 = 36

If each club member also donated an equal number of toys. It means that the total number of toys donated by the club members would be

9 × x = 9x

A total of 63 items were collected for the baskets. Therefore, the linear equation that you can use to find how many toys each club member donated would be

9x + 36 = 63

4 0
2 years ago
In a particularly sunny month, Solaire's solar panels generated 110 percent as much power as expected.What fraction of the expec
vfiekz [6]

we are given

In a particularly sunny month, Solaire's solar panels generated 110 percent as much power as expected.

so, we need to change percent into fraction to get our value

we can write

110%=\frac{110}{100}

now, we can simplify it

and we get

110%=\frac{11}{10}

so,

Solaire's solar panels generate \frac{11}{10} of the expected amount of power.............Answer

8 0
2 years ago
Read 2 more answers
A rope is 66 feet long. It is cut into two pieces such that one piece is half the length of the other. What is the length of the
dedylja [7]
So if one bit of the length, is half the size of the other bit then we can make the following equation, for x being the length of rope:

x + 2x = 66
3x = 66
x = 22

That is the length, of the smaller one (half the big one), so 2x = 44. Hence d) is your answer.

Hope I helped!
7 0
2 years ago
Read 2 more answers
For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th
Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: z=\frac{x-\mu}{\sigma}

Here z is 2.42 and μ is 790, substitute the respective values as shown.

2.42=\frac{1637-790}{\sigma}

\sigma=\frac{847}{2.42}

\sigma=350

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0
2 years ago
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