Question

Theresa is swinging a 4.0 kg ball on a 1.2 m long rope with a tangential speed of 1.8 m/s. What is the centripetal force exerted on the rope? Round to the tenths place.

Answer 1

You need to round and the answer is 10.8N

Answer 2

For this case the centripetal force is given by:

$F = m * (\frac{v^2}{r})$

Where,

m: mass of the object

v: tangential speed

r: rope radius

Substituting values in the equation we have:

$F = (4.0) * (\frac{1.8^2}{1.2})$

Then, doing the corresponding calculations:

$F = 10.8 N$

Answer:

The centripetal force exerted on the rope is:

$F = 10.8 N$