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Anastasy [175]
2 years ago
15

A dog is chasing a cat towards a tree. The cat has a 10-yard lead and runs at 6 yards per second. The dog runs at a speed of 8 y

ards per second. The tree is 30 yards away from the dog's starting position. Which animal will reach the tree first?

Physics
1 answer:
oksano4ka [1.4K]2 years ago
3 0

Answer : Cat will reach tree first.

Explanation :

It is given that,

Total distance between dog and tree is 30 yards. The cat has 10 yards lead. So, the distance between cat and tree is 20 yards.

Speed of cat  is 6 Yards/ sec.

Speed of dog is 8 Yards/sec.

speed of cat is, S_c=\dfrac{distance\ covered\ by\ cat}{time\ taken}

6\ Yards/sec=\dfrac{20\ Yards}{t_c}

t_c=3.33\ sec

Now, speed of dog is, S_d=\dfrac{distance\ covered\ by\ dog}{time\ taken}

8\ Yards/sec=\dfrac{30\ yards}{t_d \ sec}

t_d=3.75\ sec

It is clear that, cat is taking less time as compared with dog. So, the cat will reach tree first.

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A space shuttle orbits Earth at a speed of 21,000 km/hr. How far does it go in 3.5 hrs?
inn [45]
Since it travels at 21,000 kilometers per hour, you'd just multiply that with 3.5 to get 73,500. So your answer is 73,500.

5 0
2 years ago
A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.
Gekata [30.6K]

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] = 6.5*10^{4}\ m/s

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity [\theta] = 15 degree.

We are asked to calculate the magnetic force experienced by the charged  particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force \vec F=q(\ \vec V \times \vec B)

                        i.e F = =qVBsin\theta

                                   =6.8*6.5*10^{4}*1.4*sin15

                                   =61.88*10^{4}sin15

                                   =61.88*10^4*0.2588\ N

                                   =16.016*10^4\ N

                                   =1.6*10^5\ N

Hence, the force experienced by the charged particle is C i.e 1.6*10^5 N

                                   

             

4 0
2 years ago
Read 2 more answers
a 2.0 kg hoop rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear spe
e-lub [12.9K]

Answer:

72 J

Explanation:

Total kinetic energy will be tge sum of rotational and translational energy.

Rotational kinetic energy is given by 0.5I\omega^{2} where I is moment of inertia which is given by mr^{2} and here m is mass, r is radius. Also, v=\omega r hence making \omega the subject then \omega=\frac {v}{r} where v is the velocity.

Rotational kinetic energy=0.5I\omega^{2}=0.5mr^{2}\times(\frac {v}{r})^{2}= 0.5mv^{2}

This is same as the formula for translational kinetic energy which is given by 0.5mv^{2}

Therefore, total kinetic energy= 0.5mv^{2}+0.5mv^{2}=mv^{2}

Substituting m with 2 kg and v with 6 m/s then total energy will be 2\times 6^{2}=72 J

7 0
2 years ago
what velocity must a 1340kg car have in order to havw the same momentum as a 2680 kg truck traveling at a velocity of 15m/s to t
kykrilka [37]
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.

Hope i helped
Have a good day :)

 
6 0
2 years ago
Sebuah benda dijatuhkan bebas dari ketinggian 200 m jika grafitasi setempat 10 m/s maka hitunglah kecepatan dan ketinggian benda
Pie
Please post in English so i or someone else can help you.
7 0
2 years ago
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