Since it travels at 21,000 kilometers per hour, you'd just multiply that with 3.5 to get 73,500. So your answer is 73,500.
As per the question, the point charge is given as [q] = 6.8 C
The velocity of the charged particle [v] = 
The magnetic field [B] = 1.4 T
The angle made between magnetic field and velocity
= 15 degree.
We are asked to calculate the magnetic force experienced by the charged particle.
The magnetic force experienced by the charged particle is calculated as -
Magnetic force 
i.e F = 





Hence, the force experienced by the charged particle is C i.e 
Answer:
72 J
Explanation:
Total kinetic energy will be tge sum of rotational and translational energy.
Rotational kinetic energy is given by
where I is moment of inertia which is given by
and here m is mass, r is radius. Also,
hence making \omega the subject then
where v is the velocity.
Rotational kinetic energy=
This is same as the formula for translational kinetic energy which is given by 
Therefore, total kinetic energy= 
Substituting m with 2 kg and v with 6 m/s then total energy will be 
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.
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