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sertanlavr [38]
2 years ago
5

2. Draw a structural formula for 3,4-hexene (C6H12), which has a double bond between the number 3 and 4 carbons in the chain. Wh

at class of compound is it, and what feature distinguishes it as that class?
Chemistry
2 answers:
Rufina [12.5K]2 years ago
8 0
The structure will be:
H₃C-CH₂-CH=CH-CH₂-CH₃
This class of compounds is known or referred to as alkenes. Alkenes are unsaturated hydrocarbons that contain a carbon-carbon double bond. The present of this double bond alters the properties of alkenes rom alkanes.
MAVERICK [17]2 years ago
8 0

Answer:

(C₆H₁₂) 3,4-hexene demonstrating the double bond between 3rd and 4th carbon is shown below:  

CH₃-CH₂-CH=CH-CH₂-CH₃

The suffix ene signifies that it comprises double bond in it between the atoms of carbon that comes under alkene. The Greek prefix hex means 6, and in hexene, it signifies that it comprises six carbon atoms in a molecule. The double bond in the compound is found in between 3 and 4 carbons.  

This can also demonstrate symmetry that comes under symmetrical alkene in such molecule the double bonded carbons exhibit same ligands or a similar number of carbons on both the sides.  

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A 1.0-gram sample of solid iodine is placed in a tube and the tube is sealed after all of the air is removed. The tube and the s
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Answer:

27.0

Explanation:

Because Mass can neither be created nor be destroyed hence total mass of sample of iodine and tube remain equal as it is sealed.

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In the redox conversion of Ni2+ to NiO4−, the oxidation number of Ni goes from (−2, 0, +2) to (−1, +1, +7, +9). Recall that the
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Oxidation number of an atom is the charge that atom would have if the compound is composed of ions. In neutral substances that contains atoms of one element the oxidation number of an atom is zero. Thus atoms in O2, Ni2, and aluminium all have oxidation number of zero.
In this case, Ni2, the oxidation number of Ni atom is zero, 
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Which of the following statements is true about nuclear power? A) It releases greenhouse gases. B) It does not produce wastes. C
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3 0
2 years ago
A sample of a certain barium chloride hydrate, BaCl2.nH2O, has a mass of 7.62 g. When this sample is heated in a crucible, it is
Ratling [72]

Answer:

BaCl2.2H2O

Explanation:

Data obtained from the question include:

Mass of barium chloride hydrate (BaCl2.nH2O) = 7.62g

Mass of anhydrous barium chloride (BaCl2) = 6.48g

Next, we shall determine the mass of water in the barium chloride hydrate (BaCl2.nH2O). This can be obtained as follow:

Mass of water (H2O) = Mass of barium chloride hydrate (BaCl2.nH2O) – Mass of anhydrous barium chloride (BaCl2)

Mass of water (H2O) = 7.62 – 6.48

Mass of water (H2O) = 1.14g

Next, we shall write the balanced equation for the reaction. This is given below:

BaCl2.nH2O —> BaCl2 + nH2O

Next, we shall determine the masses of BaCl2.nH2O that decomposed and the mass H2O produced from the balanced equation.

Molar mass of BaCl2.nH2O = 137 + (35.5x2) + n[(2x1) + 16]

= 137 + 71 + n[2 + 16]

= (208 + 18n) g/mol

Mass of BaCl2.nH2O from the balanced equation = 1 x (208 + 18n) = (208 + 18n) g

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = n x 18 = 18n g

Summary:

From the balanced equation above,

(208 + 18n) g of BaCl2.nH2O decomposed to produce 18n g of H2O.

Finally, we shall determine the formula for the hydrated compound as follow:

From the balanced equation above,

(208 + 18n) g of BaCl2.nH2O decomposed to produce 18n g of H2O.

But 7.62g of BaCl2.nH2O decomposed to produce 1.14g of H2O i.e

18n/(208 + 18n) = 1.14/7.62

Cross multiply

18n x 7.62 = 1.14(208 + 18n)

137.16n = 237.12 + 20.52n

Collect like terms

137.16n – 20.52n = 237.12

116.64n = 237.12

Divide both side by the coefficient of n i.e 116.64

n = 237.12/116.64

n = 2

Therefore the formula for the hydrate, BaCl2.nH2O is BaCl2.xH2O.

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Igoryamba
Solar and hydroelectric (just took test)
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