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sertanlavr [38]
2 years ago
5

2. Draw a structural formula for 3,4-hexene (C6H12), which has a double bond between the number 3 and 4 carbons in the chain. Wh

at class of compound is it, and what feature distinguishes it as that class?
Chemistry
2 answers:
Rufina [12.5K]2 years ago
8 0
The structure will be:
H₃C-CH₂-CH=CH-CH₂-CH₃
This class of compounds is known or referred to as alkenes. Alkenes are unsaturated hydrocarbons that contain a carbon-carbon double bond. The present of this double bond alters the properties of alkenes rom alkanes.
MAVERICK [17]2 years ago
8 0

Answer:

(C₆H₁₂) 3,4-hexene demonstrating the double bond between 3rd and 4th carbon is shown below:  

CH₃-CH₂-CH=CH-CH₂-CH₃

The suffix ene signifies that it comprises double bond in it between the atoms of carbon that comes under alkene. The Greek prefix hex means 6, and in hexene, it signifies that it comprises six carbon atoms in a molecule. The double bond in the compound is found in between 3 and 4 carbons.  

This can also demonstrate symmetry that comes under symmetrical alkene in such molecule the double bonded carbons exhibit same ligands or a similar number of carbons on both the sides.  

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9 0
2 years ago
Read 2 more answers
When applied to a dish, soap makes grease soluble in water. Which explanation correctly supports the role of intermolecular forc
Mekhanik [1.2K]

Explanation:

Soaps attach to both water and grease molecules.

The grease molecules are attracted more strongly towards each other as compared to water molecules. Also, water molecules are smaller in size hence, strong intermolecular force is required to break the hydrogen bonds of water molecule so that grease or oil molecules can enter the water molecule.

A soap molecule goes in between water and grease molecule and helps them to bind. The force for linkage between water and grease molecule through the soap molecule is weak london dispersion force.

The soap molecule has its salt end as ionic and water soluble. When grease or oil is added to the soap and water solution then the soap acts as an emulsifier. The soap forms miscelles of the non-polar tails and grease molecules are trapped between these miscelles. This miscelle is easily soluble in water hence, the grease is washed away.

Thus, it can be concluded that the nonpolar end of a soap molecule attaches itself to grease.

7 0
2 years ago
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A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
2 years ago
Write a balanced equation for: (a) alpha decay of gold-173
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8 0
2 years ago
The Michaelis‑Menten equation models the hyperbolic relationship between [S] and the initial reaction rate V 0 V0 for an enzyme‑
ipn [44]

Answer:

The Michaelis‑Menten equation is given as

v₀ = Kcat X [E₀] X [S] / (Km + [S])

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Kcat is the experimental rate constant of the reaction; [s] is the substrate concentration and

Km is the Michaelis‑Menten constant.

Explanation:

See attached image for a detailed explanation

3 0
2 years ago
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