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igor_vitrenko [27]
2 years ago
9

Which quantity gives the best indication of the relative strength of the hydrogen bonds between the molecules in liquid hydrogen

halides?
A: bond dissociation energies
B: enthalpy changes of formation
C: enthalpy changes of solution
D: enthalpy changes of vaporization


answer is D but how
Chemistry
1 answer:
sineoko [7]2 years ago
3 0
The hydrogen bonds is an intermolecular force.

This is, it is an atracction among molecules, which trends to keep the molecules  close one to each other quite strongly.


Vaporization is the pass from liquid, where the molecules are pretty close one to each other, to gas, where the molecules are more distant from each other. To reach that separation of the molecules, the strong hydrogen bonds must be overcome, which means a higher energy requirement than in similar compounds without hydrogen bonds.

That is reflected in high values for the enthalpy of vaporization in the compounds with hydrogen bonds (like hydrogen halides).


So, that leads to the option D. of the list of answers. enthalpy heat of vaporization gives the best indication of the relative strenght of hydrogen bonds. 

 
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Explanation:

1. write out the variables given:

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3. calculate the quantity of heat evolved:

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4. calculate the molar mass of CaCl2:

Next is to calculate the molar mas of CaCl2

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The number of moles of 13.6 g of CaCl2 is then:

Number of moles of CaCl2 = mass / molar mass

Number of moles = 13.6 g / 111 g/mol

Number of moles = 0.1225 mol

So 384.09 J of heat was involved in the reaction of 1.6 g of CaCl2 in a calorimter which translates to 0.1225 mol of CaCl2..

5. Calculate the enthalpy of solution in kJ/mol:

If 1 mole of CaCl2 is involved, the heat evolved is therefore:

Heat per mole = 384.09 J / 0.1225 mol

Heat = 3 135.43 J/mol

The enthalpy of solution is therefore 3153.43 J/mol or 3.15 kJ/mol.

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