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2 years ago

4

Each of the teams in a mixed volleyball league consists of 5 men and 5 women. There are 9 men and 10 women, including Julia, who

are trying out for a team. How many possible teams would include Julia?

1 answer:

ehidna [41]2 years ago

6 0

5 spots for men and theres 9 men trying out so to find the number of combinations for men the function would be (9*8*7*6*5)/(1*2*3*4*5)=126. the function for women would be (10*9*8*7*6)/(1*2*3*4*5)=252. youd then multiply the two(126*252) and get 31,752.

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otez555 [7]

Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

Whoever had the higher z-score.

David:

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So $X = 52, \mu = 70, \sigma = 11$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{52 - 70}{11}$

$Z = -1.64$

Steven:

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So $X = 52, \mu = 64, \sigma = 6$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{52 - 64}{6}$

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Due to the higher z-score, David has the higher standardized score

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2 years ago

a crane cable can support a maximum load of 15,000 kg. if a bucket has a mass of 2,000 kg and gravel has a mass of 1,500 kg for

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Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

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Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

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Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

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$\Rightarrow -18k= ln1-ln2$

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Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

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