All categories

2 years ago

Which rule should be applied to reflect f(x)=x^3 over the y-axis?

2 answers:

7 0

To make a reflection over the y axis, make the whole equation negative.
The new equation should look like this:

f(x) = -x^3

lyudmila [28]2 years ago

4 0

Answer:

Substitute $-x$ in place for x.

Step-by-step explanation:

We have been given a function $f(x)=x^3$ . We are asked to reflect our given function over the y-axis.

We know that after reflecting a function over y-axis, the y-coordinates remains same, while sign of x-coordinates changes to opposite.

The rule of reflection of a point over y-axis is $f(x)\rightarrow f(-x)$ .

Therefore, we need to substitute $-x$ in place for x in our given function and simplify the equation.

You might be interested in

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago

An ant begins at the top of the pictured octahedron. If the ant takes two "steps", what is the probability it ends up at the bot

Aleksandr-060686 [28]

Answer:

$P_{bottom}=\frac{1}{4}=0.25$

Step-by-step explanation:

Starting from the top, the ant can only take four different directions, all of them going down, every direction has a probability of 1/4. For the second step, regardless of what direction the ant walked, it has 4 directions: going back (or up), to the sides (left or right) and down. If the probability of the first step is 1/4 for each direction and once the ant has moved one step, there are 4 directions with the same probability (1/4 again), the probability of taking a specific path is the multiplication of the probability of these two steps:

$P_{2steps}=\frac{1}{4}*\frac{1}{4}=\frac{1}{16}$