Answer:
1 1/2
Step-by-step explanation:
The first step is to figure out the lightest and the heaviest bad. The lightest bag is 4 1/4 and the heaviest is 5 3/4. Now to subtract, you can't subtract this as a mixed fraction so turn each fraction into an improper fraction by multiplying the whole number by the denominator then adding the numerator to the product of the whole number multiplied by the denominator (if you didn't know numerator is the top and the denominator is the bottom. To find out 4 1/4 as an improper fraction follow these steps (4*4+1=17) so 4 1/4=17/4. The process is the same for 5 3/4 (5*4+3=23) so 5 3/4= 23/4. Now to subtract, you subtract the numerator but not the denominator. You subtract because the question asks how many more and that means to subtract 23/4-17/4= 6/4. Last step is to turn this back into a mixed fraction do that by dividing the numerator by the denominator, 6 divided by 4 equals 1.5 and turn the decimal into a fraction 1 is a whole number so you don't change that but the 5 behind the decimal needs to be changed so now 1.5= 1 5/10 and last step is simplify 1 1/2. Hope this helped :).
Answer:
Step-by-step explanation:
9/15y + 3/21 = 5/15 y - 14/21. Adding 14/21 to both sides we then get 9/15y + 17/21 = 5/15y. Subtracting 5/15y from both sides, we get 4/15y + 17/21 = 0.
Then we get 4/15y = -17/21. Dividing by 4/15 gets us -17/21 * 4/15 = -68/315 = y.
Answer:
4
Step-by-step explanation:
Mean = sum of scores /number of scores
We have four scores given ,so, the sum of the scores given will be divided by the number of scores which is 4
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:
P(B) is the probability that the selected student plays basketball.
Then:
P(A and B) is the probability that the selected student plays soccer and basketball:
P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:
P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.
545,999 rounded to the nearest hundred thousand is 546,000.
