Question

The element carbon (C) is most likely to form covalent bonds with the element beryllium (Be). krypton (Kr). selenium (Se). sodium (Na).

Answer 1

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of carbon is 6 and its electronic configuration is 2, 4. So, in order to complete its octet, it requires 4 more electrons.

Therefore, carbon form covalent bonds, that is, it shares electrons with and electron deficient atom.

Krypton is a noble gas and has completely filled octet. So, it will neither give to share its electrons with carbon atom.

Whereas beryllium and sodium does not have enough valence electrons to share. Hence, they will not form bond with carbon atom.

On the other hand, selenium being a non-metal is electron deficient and therefore, in order to complete its octet it will share its electrons with carbon atom.

Thus, we can conclude that the element carbon (C) is most likely to form covalent bonds with the element selenium (Se).

Answer 2

 The element  that is most  likely  to form covalent  bonds  with  carbon (C)  is

Selenium  (Se)

Explanation

Covalent  bond is  formed   when  there is sharing of electrons among  two   or more non metals.

Both carbon  and selenium are non metals  therefore they  react to form  a covalent  bond  by sharing electron.

 Despite  krypton been a non metal  it does  not form a covalent  bond with carbon since krypton is  inert ( non reactive).

Beryllium (Be)  and  sodium (Na) are  metals therefore  they form  ionic bond with  carbon instead  of covalent  bond.