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katrin [286]
2 years ago
15

A student was comparing the solubility of equal amounts of table salt and table sugar at different temperatures.The table below

shows the four samples that the student used and the temperature of the water that they were dissolved in. Which of the samples most likely had the highest solubility?
Chemical formula
Temperature of water (°C)
1
Table sugar
C12H22O11
80
2
Table sugar
C12H22O11
45
3
Table salt
NaCl
55
4
Table salt
NaCl
63
Chemistry
2 answers:
alexgriva [62]2 years ago
5 0
First, we distinguish whether table sugar or table salt will be more soluble. The bonds between the molecules of the table sugar are weaker than the bonds between the molecules of salt. Therefore, it is easier for the sugar molecules to dissolve.
Next, we evaluate the effect of temperature on solubility. As the temperature of a solvent increases, it is able to hold more and more solute. This means that the sample with table sugar kept at the highest temperature will contain the most dissolved solute, and this is sample 1.
Lapatulllka [165]2 years ago
4 0

table sugar is more soluable than table salt, and higher temp is better for solubility. <em>So sample 1 works best.</em>

Answered this question and got it right, so I can confirm this is accurate.

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compare and contrast melting 10 kg of ice freezing 1 kg of water. be sure to address temperature,heat flow, and thermal energy
liraira [26]
<span>Melting is an endothermic process (i.e. it absorbs heat), whereas freezing is an exothermic process (i.e. it releases heat, or can be thought of, albeit incorrectly from a thermodynamics standpoint, as "absorbing cold"). The standard enthalpy of fusion of water can be used for both scenarios, but standard enthalpy is in units of energy/mass, so 10 times as much energy will be absorbed in the former scenario (melting 10 kg of ice) than what will be absorbed in the latter scenario (freezing 1 kg of water). For both processes, assuming the water is pure and at standard atmospheric pressure, and the entire mass remains at thermal equilibrium, the temperature of both the solid and the liquid will remain at precisely 0 degrees Celsius (273 K) for the duration of the phase change.</span>
6 0
2 years ago
Olive oil has a density of 0.92g/ml. How much would 1.0 Liter of olive oil weigh in grams?
Julli [10]

Answer:

9.2x10²g

Explanation:

Data obtained from the question include the following:

Density = 0.92g/ml

Volume = 1L = 1 x 1000 = 1000mL

Mass =..?

Density is simply defined as the mass of the substance per unit volume of the substance. Mathematically it can be represented as:

Density = Mass /volume.

Mass = Density x volume

Mass = 0.92 x 1000

Mass = 9.2x10²g.

Therefore, 1L of olive will weigh 9.2x10²g.

5 0
2 years ago
Be sure to answer all parts. For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g)
Liono4ka [1.6K]

Answer:

a. -268.13 J/K

b. -279.95 J/K

c. + 972.59 J/K

Explanation:

The value of the change in entropy (ΔS°) can be calculated by:

ΔS° = ∑n*S° products - ∑n*S° reactants, where n is the stoichiometric number of moles.

The values of S° for each substance can be found on a thermodynamic table.

a. 3NO2(g) + H2O(l) → 2HNO3(l) + NO(g)

S°, NO2(g) = 240.06 J/mol.K

S°, H2O(l) = 69.91 J/mol.K

S°, HNO3(l) = 155.60 J/mol.K

S°, NO(g) = 210.76 J/mol.K

ΔS° = (210.76 + 2*155.60) - (3*240.06 + 69.91)

ΔS° = -268.13 J/K

b. N2(g) + 3F2(g) → 2NF3(g)

S°, N2(g) = 191.61 J/mol.K

S°, F2(g) = 202.78 J/mol.K

S°, NF3(g) = 260.0 J/mol.K

ΔS° = (2*260.0 ) - (191.61 + 3*202.78)

ΔS° = -279.95 J/K

c. C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(g)

S°, C6H12O6(s) = 212 J/mol.K

S°, O2(g) = 205.138 J/mol.K

S°, CO2(g) = 213.74 J/mol.K

S°, H2O(g) = 188.83 J/mol.K

ΔS° = (6*213.74 + 6*188.83) - (212 + 6*205.138)

ΔS° = +972.59 J/K

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vovikov84 [41]

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Among the given statements the following statements are true-

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The statements which are not true for the Diels-Alder reaction:

3. The re-crystallization of the products by any polar solvent like methanol is not feasible as it will cause the retro reaction due to stability of the transition state in polar solvent.

4. Cleaning of glassware are compulsory for any reaction it is not specifically true for Diels-Alder reaction.

5. The reaction occurs at elevated temperature thus flame is required.

 

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denis23 [38]
D has a total of four significant figures.
7 0
2 years ago
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