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Sati [7]
2 years ago
13

Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with co

nstant velocity. Which best describes Deena’s error?
The line for constant velocity is not horizontal; it is diagonal and slopes downward.

Include the area of the rectangle under the line to find displacement for constant acceleration.

Find acceleration by finding the area of the rectangle above the line.

Find velocity by calculating the slope of the line.
Physics
2 answers:
Irina-Kira [14]2 years ago
5 0
The error is:
"<span>Find acceleration by finding the area of the rectangle above the line"

The acceleration of any body is the rate of change of velocity of that body. If the motion of the object being considered is plotted on a graph, with the velocity on the y-axis and the time on the x-axis, this ratio will be equivalent to the slope of the graph, not the area above the line.</span>
goldenfox [79]2 years ago
4 0

Answer:

Include the area of the rectangle under the line to find displacement for constant acceleration.

Explanation:

correct on edge

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Let’s consider tunneling of an electron outside of a potential well. The formula for the transmission coefficient is T \simeq e^
ioda

Answer:

L' = 1.231L

Explanation:

The transmission coefficient, in a tunneling process in which an electron is involved, can be approximated to the following expression:

T \approx e^{-2CL}

L: width of the barrier

C: constant that includes particle energy and barrier height

You have that the transmission coefficient for a specific value of L is T = 0.050. Furthermore, you have that for a new value of the width of the barrier, let's say, L', the value of the transmission coefficient is T'=0.025.

To find the new value of the L' you can write down both situation for T and T', as in the following:

0.050=e^{-2CL}\ \ \ \ (1)\\\\0.025=e^{-2CL'}\ \ \ \ (2)

Next, by properties of logarithms, you can apply Ln to both equations (1) and (2):

ln(0.050)=ln(e^{-2CL})=-2CL\ \ \ \ (3)\\\\ln(0.025)=ln(e^{-2CL'})=-2CL'\ \ \ \ (4)

Next, you divide the equation (3) into (4), and finally, you solve for L':

\frac{ln(0.050)}{ln(0.025)}=\frac{-2CL}{-2CL'}=\frac{L}{L'}\\\\0.812=\frac{L}{L'}\\\\L'=\frac{L}{0.812}=1.231L

hence, when the trnasmission coeeficient has changes to a values of 0.025, the new width of the barrier L' is 1.231 L

8 0
2 years ago
7. A local sign company needs to install a new billboard. The signpost is 30 m tall, and the ladder truck is parked 24 m away fr
wolverine [178]
<h2>Solution :</h2>

Here ,

• Height of sign post = 30 m

• Distance between signpost and truck = 24 m

Let the

• Top of signpost = A

• Bottom of signpost = B

• The end of truck facing sign post be = C

Now as we can clearly imagine that the ladder will act as an hypotenuse to the Triangle ABC .

Where

• AB = Height of signpost = 30 m

• BC = distance between both = 24 m

• AC = Minimum length of ladder

→ AC² = AB² + BC² ( As we can see AB is perpendicular to BC )

→ AC² = (30)² + (24)²

→ AC² = 900 + 576

→ AC² = 1476

→ AC = 38.41875

or AC apx = 38.42

So minimum height of ladder = 38.42

6 0
2 years ago
You are playing a game called "Will It Float?" In this game, you are given a large, square can of tuna. If you know the density
Delicious77 [7]
The only information you would need to decide if the can will float is the density of the can, which requires knowing the mass and volume. If the density of the can is less than one, the can will float. if it is greater than one, it will not float, as water's density is one.
6 0
2 years ago
Read 2 more answers
The speed v of a sound wave traveling in a medium that has bulk modulus b and mass density ρ (mass divided by the volume) is v=b
PilotLPTM [1.2K]

As it is given that Bulk modulus  and density related to velocity of sound

v = \sqrt{\frac{B}{\rho}}

by rearranging the equation we can say

B = \rho * v^2

now we need to find the SI unit of Bulk modulus here

we can find it by plug in the units of density and speed here

B = \frac{kg}{m^3} * (\frac{m}{s})^2

so SI unit will be

B = \frac{kg}{m* s^2}

SO above is the SI unit of bulk Modulus

3 0
2 years ago
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Sladkaya [172]

Answer: c. increased sensitivity to ADH

Explanation:

a. a decline in the number of functional nephrons: With aging the loss of nephron occurs that can be detected by the age related decrease in the glomerular filteration rate.

b. a reduction in the GFR (glomerular filtration rate): The GFR tend to decline in older age even though there is no disease. These people are required to check with the GFR in future.

d. problems with the micturition reflex: With aging people experience problem of bladder control. This leads to leakage or incontinence of urine or urinary retention that is inability to empty the bladder.

e. loss of sphincter muscle tone: With age the sphincter tone may diminish. This results in loss of control and storage capacity. The rectal muscles or sphincter muscles get loose which lead to passage of stool before reaching the washroom.

6 0
2 years ago
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