Answer:
The height of the wave is determined by the wind strength and fetch.
Explanation:
The height of the wave is determined by the wind strength and fetch.
The more the strength and the more the fetch size the more will be the height of the wave.
Remember as the wave approaches the coast its wavelength decreases and the wave height increases, whereas when the wave goes away from the coast its wavelength increases and height decreases.
Answer:
Tangential velocity = 10.9 m/S
Explanation:
As per the data given in the question,
Force = 20 N
Time = 1.2 S
Length = 16.5 cm
Radius = 33.0 cm
Moment of inertia = 1200 kg.cm^2 = 1200 × 10^(-4) kg.m^2
= 1200 × 10^(-2) m^2
Revolution of the pedal ÷ revolution of wheel = 1
Torque on the pedal = Force × Length
= 20 × 16.5 10^(-2)
= 3.30 N m
So, Angular acceleration = Torque ÷ Moment of inertia
= 3.30 ÷ 12 × 10^(-2)
= 27.50 rad ÷ S^2
Since wheel started rotating from rest, so initial angular velocity = 0 rad/S
Now, Angular velocity = Initial angular velocity + Angular Acceleration × Time
= 0 + 27.50 × 1.2
= 33 rad/S
Hence, Tangential velocity = Angular velocity × Radius
= 33 × 33 × 10^(-2)
= 10.9 m/S
<h2>Apartment Explosion Reported </h2>
The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. The heat increased the temperature of the air in the room, which means an increase in the air's molecular kinetic energy.
When heat is provided then temperature increases and the molecules of substances move rapidly by increase of kinetic energy (K.E) temperature increases. It is understood that heat increases temperature.
Two significant figures, the 6 and the 9
The static friction exerted on the block by the incline is 
.
The given parameters;
- <em>mass of the block, = M</em>
- <em>coefficient of static friction in section 1, = </em>
<em /> - <em>angle of inclination of the plane, = θ</em>
<em />
The normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;
Thus, the static friction exerted on the block by the incline is
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