Answer:
From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases
Explanation:
I cannot find any attached photo, but we can proceed anyways theoretically.
The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point
i.e

But the force F

But the electric field intensity due to a point charge Q at a distance r meters away is given by

<em>From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases</em>
Answer:
B.
Explanation:
One of the ways to address this issue is through the options given by the statement. The concepts related to the continuity equation and the Bernoulli equation.
Through these two equations it is possible to observe the behavior of the fluid, specifically the velocity at a constant height.
By definition the equation of continuity is,

In the problem
is
, then


<em>Here we can conclude that by means of the continuity when increasing the Area, a decrease will be obtained - in the diminished times in the area - in the speed.</em>
For the particular case of Bernoulli we have to


For the previous definition we can now replace,


<em>Expressed from Bernoulli's equation we can identify that the greater the change that exists in pressure, fluid velocity will tend to decrease</em>
The correct answer is B: "If we increase A2 then by the continuity equation the speed of the fluid should decrease. Bernoulli's equation then shows that if the velocity of the fluid decreases (at constant height conditions) then the pressure of the fluid should increase"
Answer:
Explanation:
To convert gram / centimeter³ to kg / m³
gram / centimeter³
= 10⁻³ kg / centimeter³
= 10⁻³ / (10⁻²)³ kg / m³
= 10⁻³ / 10⁻⁶ kg / m³
= 10⁻³⁺⁶ kg / m³
= 10³ kg / m³
So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³
2.33 gram / cm³
= 2.33 x 10³ kg / m³ .
Answer:
a) V_a = -5.7536 10⁺⁷ V
, b) Vb = -1.92 10⁻⁷ V c) the sign of the potential change
Explanation:
The electrical potential for a point charge
V = k q / r
Where k is the Coulomb constant that you are worth 8.99 10⁹ N m² / C²
a) potential At point x = 0.250 cm = 0.250 10-2m
V_a = -8.99 10⁹ 1.6 10⁻¹⁹ /0.250 10⁻²
V_a = -5.7536 10⁺⁷ V
b) point x = 0.750 cm = 0.750 10-2
Vb = 8.99 10⁹ (-1.6 10⁻¹⁹) /0.750 10⁻²
Vb = -1.92 10⁻⁷ V
potemcial difference
ΔV = Vb- Va
V_ba = (-5.7536 + 1.92) 10⁻⁷
V_ba = -3.83 10⁻⁷ V
c) To know what would happen to a particle, let's use the relationship between the potential and the electric field
ΔV = E d
The force on the particle is
F = q₀ E
F = q₀ ΔV / d
We see that the force on the particle depends on the sign of the burden of proof. Now the burden of proof is negative to pass between the two points you have to reverse the sign of the potential, bone that the value should be reversed
V_ba = 0.83 10⁻⁷ V