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Elena L [17]
2 years ago
15

A soccer player kicks a ball down the field. It rolls to a stop just before the goal. Which statement accurately describes the m

otion of the soccer ball?
A. Inertia moves the ball until it runs out of force
B. The ball loses inertia due to an unbalanced force.
C. A balanced force keeps the ball in motion until it stops.
D. An unbalanced force causes the ball to stop.
Physics
1 answer:
brilliants [131]2 years ago
6 0

B

When the ball was kicked it gained inertia of motion. Inertia is the tendency of an object (in motion or rest) to keep at uniform motion or rest, and in a straight line, unless an external force acts on the object.

Explanation:

The ball kept moving due to inertia in its motion, however, there was an external force acting on the ball which caused it to reduce speed until it came to a standstill. This force is friction with the ground. The friction converted most of the inertia energy into friction and some lost as heat energy until the ball lost most of force to keep moving into the goal.

Learn More:

For more on inertia check out;

brainly.com/question/12791758

brainly.com/question/10379026

#LearnWithBrainly

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Tpy6a [65]

Answer:

For series connected resistors I = 0.5A

For parallel connected resistors I = 8.5A

Explanation:

Since the diagram is not available, our solution will be divided into two;

According to ohm's law which states that "the current passing through a,metallic conductor at constant temperature is directly proportional to the potential difference across its ends. Mathematically, E = IRt where;

E is the electromotive force

I is the total current in the circuit

Rt is total equivalent resistance.

Where E = 12volts

Rt can be gotten depending on the arrangements of the resistors which can either be in series or parallel.

If the resistors are in series, their equivalent resistance gives;

Rt = 4.0Ω+6Ω+8Ω+6Ω

Rt = 24Ω

The current I will be;

I = E/Rt = 12/24

I = 0.5A

If the connection is in series, the total current in the circuit will be 0.5A.

For resistance in parallel;

1/Rt = 1/4Ω+1/6Ω+1/8Ω+1/6Ω

1/Rt = 6+4+3+4/24

1/Rt = 17/24

Rt = 24/17Ω

I = E/Rt

I = 12/(24/17)

I = 12×17/24

I = 8.5A

If the connection is in parallel, the total current in the circuit will be 8.5A

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kirill115 [55]

Answer:

the 70kg man

Explanation:

because he has more weight and is moving faster

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Charge q1 is distance r from a positive point charge q. charge q2=q1/3 is distance 2r from q. what is the ratio u1/u2 of their p
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We need the power law for the change in potential energy (due to the Coulomb force) in bringing a charge q from infinity to distance r from charge Q. We are only interested in the ratio U₁/U₂, so I'm not going to bother with constants (like the permittivity of space). 

<span>The potential energy of charge q is proportional to </span>
<span>∫[s=r to ∞] qQs⁻²ds = -qQs⁻¹|[s=r to ∞] = qQr⁻¹, </span>

<span>so if r₂ = 3r₁ and q₂ = q₁/4, then </span>
<span>U₁/U₂ = q₁Qr₂/(r₁q₂Q) = (q₁/q₂)(r₂/r₁) </span>
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Driving a motor vehicle requires many coordinated functions which are impacted by alcohol and other drugs
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I am assuming this is a true or false question, to which the answer would be True.

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If the rocket has an initial mass of 6300 kg and ejects gas at a relative velocity of magnitude 2000 m/s , how much gas must it
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Answer:

The amount of gas that is to be released in the first second in other to attain an acceleration of  27.0 m/s2  is

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Explanation:

From the question we are told that

   The mass of the rocket is m = 6300 kg

   The velocity at gas is being ejected is  u =  2000 m/s

    The initial acceleration desired is a =  27.0 \  m/s

   The time taken for  the gas to be ejected is  t = 1 s

Generally this desired acceleration is mathematically represented as

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Here \frac{\Delta m}{\Delta  t }  is the rate at which gas is being ejected with respect to time

Substituting values

      27 = \frac{2000 *  \frac{\Delta m}{\Delta t} }{6300 -\frac{\Delta m}{\Delta t}* 1}

=>   170100 -27* \frac{\Delta m}{\Delta t} = 2000 *  \frac{\Delta m}{\Delta t}

=>   170100  = 2027 *  \frac{\Delta m}{\Delta t}

=>   \frac{\Delta m}{\Delta t}   = \frac{170100}{2027}

=>   \frac{\Delta m}{\Delta t}   = 83.92 \ Kg/s

     

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