Answer: 15.8
Explanation:
You are given that the
Object distance U = 32 cm
Focal length F = 30.1 cm
First calculate the image distance V by using the formula
1/F = 1/U + 1/V
Substitute F and V into the formula
1/30.1 = 1/32 + 1/V
1/V = 1/30.1 - 1/32
1/V = 0.00197259
Reciprocate both sides
V = 506.94 cm
Magnification M is the ratio of image distance to object distance.
M = V/U
substitute the values of V and U into the formula
M = 506.94/32
M = 15.8
Therefore, the magnification of the image is 15.8 or approximately 16.
Answer:
false.
Explanation:
Ok, we define average velocity as the sum of the initial and final velocity divided by two.
Remember that the velocity is a vector, so it has a direction.
Then when she goes from the 1st end to the other, the velocity is positive
When she goes back, the velocity is negative
if both cases the magnitude of the velocity, the speed, is the same, then the average velocity is:
AV = (V + (-V))/2 = 0
While the average speed is the quotient between the total distance traveled (twice the length of the pool) and the time it took to travel it.
So we already can see that the average velocity will not be equal to half of the average speed.
The statement is false
Answer:
(E) The two objects reach the bottom of the incline at the same time.
Explanation:
Given;
first object with mass, m
second object with mass, 5m
The acceleration of gravity for both object is the same = 9.8 m/s²
Since both objects have the same acceleration of gravity, and no external force due friction (frictionless inclined plane), they will reach bottom of the inclined at the time.
Thus, the acceleration due to gravity is constant for all objects regardless of their masses.
Therefore, the correct option is E;
(E) The two objects reach the bottom of the incline at the same time.
The resultant motion is given by pithagoras, since the two components (north and east) are perpendicular to each other.
They are asking you about the direction so you have to use trigonometry, finding that the direction is Ф=arctan(3.8/12)=17.57° north of east.
Answer:
Explanation:
Two frequencies with magnitude 150 Hz and 750 Hz are given
For Pipe open at both sides
fundamental frequency is 150 Hz as it is smaller
frequency of pipe is given by
where L=length of Pipe
v=velocity of sound
for n=1
and f=750 is for n=5
thus there are three resonance frequencies for n=2,3 and 4
For Pipe closed at one end
frequency is given by
for n=0
for n=2
Thus there is one additional resonance corresponding to n=1 , between 
and 
