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2 years ago

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Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0× 10 12 electrons are added to sphere A, then

the two spheres are separated. Part A Afterward, what is the charge of sphere A? Express your answer with the appropriate units. q A q A = nothing nothing SubmitRequest Answer Part B Afterward, what is the charge of sphere B? Express your answer with the appropriate units. q B q B = nothing nothing SubmitRequest Answer Provide Feedback Next

1 answer:

Vilka [71]2 years ago

8 0

Answer:

8 x 10^-8 C on both the spheres.

Explanation:

Number of electrons added to A = 1 x 10^12

As the sphere A and B are identical to each other so the charge is shared equally.

Charge of one electron = 1.6 x 10^-19 C

Charge on A after wards

= number of electrons after wards x charge of one electron

qA = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

Similarly, the charge on sphere B afterwards

= number of electrons after wards x charge of one electron

qB = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

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Given that,

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We need to calculate the force on 130 cm side

Using formula of force

$F_{130}=ILB\sin\theta$

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Using formula of force

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2 years ago

The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit

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Answer:

fr = ½ m v₀²/x

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2 years ago

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Answer:

Explanation:

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2 years ago