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Vitek1552 [10]
2 years ago
15

Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0× 10 12 electrons are added to sphere A, then

the two spheres are separated. Part A Afterward, what is the charge of sphere A? Express your answer with the appropriate units. q A q A = nothing nothing SubmitRequest Answer Part B Afterward, what is the charge of sphere B? Express your answer with the appropriate units. q B q B = nothing nothing SubmitRequest Answer Provide Feedback Next
Physics
1 answer:
Vilka [71]2 years ago
8 0

Answer:

8 x 10^-8 C on both the spheres.

Explanation:

Number of electrons added to A = 1 x 10^12

As the sphere A and B are identical to each other so the charge is shared equally.

Charge of one electron = 1.6 x 10^-19 C

Charge on A after wards

= number of electrons after wards x charge of one electron

qA = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

Similarly, the charge on sphere B afterwards

= number of electrons after wards x charge of one electron

qB = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

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Which of the following characteristics of Earth's relationship to the Sun explains the existence of Earth's seasons? Choose all
Aneli [31]

Answer:

Earth's axis is tilted relative to its orbital plane.

Earth orbits around the Sun, completing one orbit each year

Explanation:

The earth tilt at an angle causes the sun rays to hit the earth surface around the globe differently. Due to the oblique angle that the rays hit the subtropics and poles, there is less heat intensity compared to the equator where the sun rays hit the earth's surface at a more or less right angle.

The earth rotation around the sun also causes seasons coupled with the earth’s tilts. As the earth rotates, in one point in the orbit, the northern or southern hemispheres will be tilted towards the sun. The phenomenon varies the local temperatures of particular regions of the earth hence driving seasonal climatic changes.

6 0
2 years ago
A pump moves water horizontally at a rate of 0.02 m3/s. Upstream of the pump where the pipe diameter is 90 mm, the pressure is 1
victus00 [196]

Answer:

the efficiency of hydralic is 79.88%

Explanation:

convert mm to m

1mm = (1/1000)m

diameter of pipe upsteam

d₁= 90mm= 0.09m

diameter of pipe downsteam

d₂= 30mm = 0.03m

finding velocity of upsteam

recall Q=A₁V₁

V₁=Q/A₁

V₁=3.14m/s

velocity of downsteam

V₂= Q/A₂

V₂= 28.29m/s

mass flow rate

m= ρQ

ρ is the density of water

m = 1000× 0.02

m= 20kg/s

the efficiency of hydralic is 79.88%

6 0
1 year ago
A metal disk weighing 1 N is resting on an index card that is balanced on top of a glass. When the index card is quickly pulled
Burka [1]
Answer: D



Step by step explanation:
8 0
2 years ago
Read 2 more answers
Two forces F1 and F2 act on a 5.00 kg object. Taking F1=20.0N and F2=15.00N, find the acceleration of the object for the configu
Anit [1.1K]
A) mass m with F1 acting in the positive x direction and F2 acting perpendicular in the positive y direction<span>

m = 5.00 kg
F1=20.0N  ... x direction
F2=15.00N</span><span>  ... y direction

Net force ^2 = F1^2 + F2^2 = (20N)^2 + (15n)^2 =  625N^2 =>

Net force = √625 = 25N

F = m*a => a = F/m = 25.0 N /5.00 kg = 5 m/s^2

Answer: 5.00 m/s^2

b) mass m with F1 acting in the positive x direction and F2 acting on the object at 60 degrees above the horizontal. </span>

<span>m = 5.00 kg
F1=20.0N  ... x direction
F2=15.00N</span><span>  ... 60 degress above x direction

Components of F2

F2,x = F2*cos(60) = 15N / 2 = 7.5N

F2, y = F2*sin(60) = 15N* 0.866 = 12.99 N ≈ 13 N


Total force in x = F1 + F2,x = 20.0 N + 7.5 N = 27.5 N

Total force in y = F2,y = 13.0 N

Net force^2 = (27.5N)^2 + (13.0N)^2 = 925.25 N^2 = Net force = √(925.25N^2) =

= 30.42N

a = F /m = 30.42 N / 5.00 kg = 6.08 m/s^2

Answer: 6.08 m/s^2


</span>
8 0
1 year ago
Read 2 more answers
To practice Problem-Solving Strategy 25.1 Power and Energy in Circuits. A device for heating a cup of water in a car connects to
jeyben [28]

Answer:

The time to boil the water is 877 s

Explanation:

The first thing we must do is calculate the external resistance (R) of the circuit, from the description we notice that it is a series circuit, by which the resistors are added

    V = i (r + R)

We replace we calculate

     r + R = V / i

     R = v / i - r

     R = 10/12 -0.04

     R = 0.793 Ω

We calculate the power supplied

     P = V i = I² R

     P = 12² 0.793

     P = 114 W

This is the power dissipated in the external resistance

We use the relationship, that power is work per unit of time and that work is the variation of energy

     P = E / t

     t = E / P

     t = 100 10³/114

     t = 877 s

The time to boil the water is 877 s

4 0
2 years ago
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