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2 years ago

Simplify the expression (1/4ab)^-2

Mathematics

2 answers:

Neko [114]2 years ago

8 0

(1/4ab)^(-2)
(1/4)^(-2)(a)^(-2)(b)^(-2)
(4)^(2)(1/a(^2))(1/b(^2))
16/((a^2)(b^2))

Dmitrij [34]2 years ago

8 0

Answer:

$\frac{16}{a^{2}b^{2}}$

Step-by-step explanation:

we have

$(\frac{1}{4}ab)^{-2}$

Remember that

$(\frac{a}{b})^{-x}=(\frac{b}{a})^{x}=\frac{b^{x}}{a^{x}}$

$(\frac{1}{4}ab)^{-2}=(\frac{4}{ab})^{2}=\frac{16}{a^{2}b^{2}}$

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A rare coin appreciates at a rate of 5.2% a year. If the initial value of the coin is $500, after how many years will its

Kisachek [45]

Answer: 36 years

Step-by-step explanation:

Exponential equation to represent growth:-

$y=A(1+r)^t$ , where A is the initial value , r is the rate of growth and t is the time period.

Given : A rare coin appreciates at a rate of 5.2% a year. If the initial value of the coin is $500.

i.e. Put A= 500 and r= 0.052 in the above formula.

The amount after t years:

$y=500(1.052)^t$

Inequality for value cross $3,000 mark:

$3000$

Divide both sides by 500

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2 years ago

12x+7<−11 AND5x−8≥4012

Arte-miy333 [17]

Answer:

No solution

Step-by-step explanation:

Given: $12x+7$ and $5x-8\geq 40$

Solve both inequality separately.

$12x+7$ Subtraction property of inequality

$12x$

$x$

and

$5x-8\geq 40$ Addition property of inequality

$5x\geq 40+8$

$5x\geq 48$

$x\geq \dfrac{48}{5}$

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

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2 years ago

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The function y = square root sign x is translated using the rule (x, y) → (x – 7, y + 2)to create f(x). What is the domain of f(

Mama L [17]

Answer:

Second option {x | x > 7}

Step-by-step explanation:

We have the function

$y = \sqrt{x}$

We know that the square root of a negative number has no solution in the real ones. Therefore the domain of this function is $x > 0$

When applying the transformation:

$(x, y) \to (x - 7, y + 2)$ we have a translation of the original function in 7 units to the right and 2 units to the top:

$f(x) = \sqrt{x-7} + 2$

In the same way we must guarantee that $(x-7)> 0$

Then $x > 7$ .

Therefore the domain of f(x) is {x | x > 7}

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2 years ago

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Adam is using the equation (x)(x + 2) = 255 to find two consecutive odd integers with a product of 255. When Adam solves the pro

kondaur [170]

$\bf (x)(x+2)=255\implies x^2+2x=255\implies x^2+2x-255=y
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2 years ago

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MA_775_DIABLO [31]

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