Answer:26
Step-by-step explanation:
Y=1.25^x-2/5-10
Take log of both sides
So Y+10=1.25^x-2/5
So log to base 10 of the two sides of the equation is
Log(Y+10)=X-2/5log1.25.
To make X the subject, divide both sides by log1.25.
Log(Y+10)/log1.25=X-2/5.
Recall that Y was given to be 115
It becomes log(115 +10)/Log1.25=x-0.4
21.64=x-0.4
X=25.6
27. Replace b with 7, making 6 + 3(7). The 3 and parentheses of 7 hint multiplication, so you multiply to make 21, then add 6 relating back to PEMDAS to teach you the correct order to solve the problem.
Answer:
A: -2
Step-by-step explanation:
You want some factor k such that k(5x) +(10x) = 0. That is, 5k+10 = 0. The solution to this is k=-2, corresponding to selection A.
Answer:
Step-by-step explanation:
It's given in this question,
m∠2 = 41°, m∠5 = 94° and m∠10 = 109°
Since, ∠2 ≅ ∠9 [Alternate interior angles]
m∠2 = m∠9 = 41°
m∠8 + m∠9 + m∠10 = 180° [Sum of angles at a point of a line]
m∠8 + 41 + 109 = 180
m∠8 = 180 - 150
m∠8 = 30°
Since, m∠2 + m∠7 + m∠8 = 180° [Sum of interior angles of a triangle]
41 + m∠7 + 30 = 180
m∠7 = 180 - 71
m∠7 = 109°
m∠6 + m∠7 = 180° [linear pair of angles]
m∠6 + 109 = 180
m∠6 = 180 - 109
= 71°
Since m∠5 + m∠4 = 180° [linear pair of angles]
m∠4 + 94 = 180
m∠4 = 180 - 94
m∠4 = 86°
Since, m∠4 + m∠3 + m∠9 = 180° [Sum of interior angles of a triangle]
86 + m∠3 + 41 = 180
m∠3 = 180 - 127
m∠3 = 53°
m∠1 + m∠2 + m∠3 = 180° [Angles on a point of a line]
m∠1 + 41 + 53 = 180
m∠1 = 180 - 94
m∠1 = 86°
90
55+65=120
there are 3 numbers and when you divide them it makes 70.
70 x 3 = 210
210 - 120 = 90
55 + 65 + 90 = 210
210 / 3 = 70
