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o-na [289]
2 years ago
8

American energy review reported that 27% of american households burn wood. if a random sample of 500 american households is sele

cted find the mean, variance, and standard deviation of the number of households that burn wood.
Business
1 answer:
Juli2301 [7.4K]2 years ago
4 0

This is binomial distribution problem. <span>
We are given that:</span>

n = sample size = 500

p = proportion which burns wood = 0.27,

q = proportion which does not burn wood = 1-p = 0.73 

<span>
A. Mean is calculated as:</span>

Mean = n*p

Mean = 500 * 0.27

Mean = 135 

<span>
B. Variance is calculated as:</span>

Variance = n*p*q

Variance = 500*0.27*0.73

Variance = 98.55 

<span>
C. Standard deviation is calculated as:</span>

Standard deviation = sqrt(variance)

Standard deviation = sqrt(98.55)

<span>Standard deviation = 9.93</span>

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