2 years ago

Find the 16th term of the series 7+2-3-8-13-•••••••••

1 answer:

8 0

Common difference is -5.
Thus, this will be an arithmetic series.

Sum is given by:
$a_n = \frac{n}{2}[2a_1 + (n - 1)d]$
$a_{16} = \frac{16}{2}[2(7) + (16 - 1)(-5)]$
$= 8[14 + (15)(-5)]$
$= 8[14 - 75]$
$= 8(-61)$
$= -488$

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Option B: $\frac{1}{(m-4)(m-3)}$ is the correct answer.

Explanation:

The given expression is $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$

Simplifying the expression, we have,

$\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}$

Factor the equations, $m^{2}-16\right$ and $m^{2}-9$ ,we get,

$m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)$

$m^{2}-9=m^{2}-3^2=(m+3)(m-3)$

Substituting these factored expressions in the above expression, we have,

$\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}$

Cancelling the common terms $m+3$ and $m+4$ , we get,

$\frac{1}{(m-4)(m-3)}$

Thus, the expression equivalent to $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$ is $\frac{1}{(m-4)(m-3)}$

Hence, Option B is the correct answer.

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Answer:

58 times 0.17 which agrees with answer C in the given list of possible answers.

Step-by-step explanation:

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Now to find the 17% of the number 58, we need to multiply 58 by 17/100, which gives:

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