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Delvig [45]
2 years ago
3

The area of the rectangle MNPQ is 588 cm^2.

Mathematics
1 answer:
andreev551 [17]2 years ago
8 0
Given:
Area of the rectangle = 588 cm²
Length = 28 cm
Width = ?

1588cm² = 28cm * w
588cm²/28cm = w
21cm = width.

Length of MP. Hypotenuse a right triangle.

a² + b² = c²
28² + 21² = c²
784 + 441 = 1225
c = √1225
c = 35 cm  length of MP.

sin
θ = Opposite / Hypotenuse
sinθ = 21cm/35cm
sinθ = 0.60 

y = sin⁻¹(0.6)   *get the angle. 
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Answer:

students preferred alternative music

= 461/1940 ×100%=23.7%

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Eliza’s backpack weighs 18 and StartFraction 7 over 9 EndFraction pounds with her math book in it. Without her math book, her ba
kramer

Answer:

about 3.9 lbs

Step-by-step explanation:

18 7/9 lbs - 14 7/8 lbs

convert mixed numbers to improper fractions

169/9 - 119/8

convert to common denominator

1352/72 - 1071/72

subtract numerators

281/72

about 3.9 lbs

4 0
2 years ago
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Korey’s comic book store has been up and running for 4 years. Korey feels that his store has been successful and is considering
Inessa05 [86]
Year      Net Profit
1            <span>$14,250.00
2            $15,390.00
3            $16,621.20
4            $17,950.90</span>2

We need to get the increase of the net profit of the current year from the previous year.

Percentage increase = (Current year - Previous Year)/ Previous Year    * 100%

Year 2:  (15,390 - 14, 250) / 14,250   * 100% = 0.08 * 100% = 8%
Year 3: (16,621.20 - 15,390) / 15,390 * 100% = 0.08 * 100% = 8%
Year 4: (17,950.90 - 16,621.20) / 16,621.20 * 100% = 0.08 * 100% = 8%

Every year the net income increases by 8%. So, the net income in Year 5 will be:

17,950.90 x 1.08 = 19,386.97  Choice D.

8 0
2 years ago
Read 2 more answers
A car manufacturer is reducing the number of incidents with the transmission by issuing a voluntary recall. During week 10 of th
Digiron [165]

Answer:

f(x) = -5x + 250

Step-by-step explanation:

* Lets  explain how to solve the problem

- In week 10 the manufacturer fixed 200 cars

- In week 15, the manufacturer fixed 175 cars

- the reduction in the number of cars each week is linear

- The form of the linear equation is y = mx + c, where m is the slope of

 the line which represent the equation and c is the y-intercept

- The slope of the line m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

  where (x1 , y1) and (x2 , y2) are two points on the line

* Lets solve the problem

- Assume that the weeks' number is x and the cars' number is y

∴ (10 , 200) and (15 , 175) are two points on the line which represent

  the linear equation between the cars' numbers and the weeks

  numbers

∵ Point (x1 , y1) is (10 , 200) and point (x2 , y2) is (15 , 175)

∴ x1 = 10 , x2 = 15 and y1 = 200 and y2 = 175

- Use the rule of the slope above to find m

∴ m=\frac{175-200}{15-10}=\frac{-25}{5}=-5

- Substitute the value of x in the form of the linear equation above

∴ y = -5x + c

- To find c substitute x and y by one the coordinates of one of the

  two points

∵ x = 10 when y = 200

∴ 200 = -5(10) + c

∴ 200 = -50 + c

- Add 50 to both sides

∴ 250 = c

- Substitute the value of c by 250

∴ y = -5x + 250, where the number of cars seen each week is y and

  x is the number of the week

∵ f(x) = y

∴ f(x) = -5x + 250

7 0
2 years ago
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MakcuM [25]

Answer:

The cost is $9.70 per kilogram.

Step-by-step explanation:

This can be solved by a rule of three.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.

Solution:

The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:

1 pound - xkg

2.2 pound - 1 kg

2.2x = 1

x = \frac{1}{2.2}

x = 0.45kg

Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?

$4.40 - 0.45kg

$x - 1kg

0.45x = 4.40

x = \frac{4.40}{0.45}

x = 9.70

The cost is $9.70 per kilogram.

6 0
2 years ago
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