Answer:
The other signal that would indicate the presence of a C= C bond appears close to 3100
.
Explanation:
Bands that appear above 3000
are often unsaturation diagnoses suggest. The band at 3000-
3100
is characteristics for C-H stretching frequencies and normally is overlaps with the ones for alkanes because it is a band of weak intensity.
Answer:
The two constitutionally isomeric compounds that result from the reaction between sodium nitrite (NaNO2) and 2−Iodooctane are the following:
Answer:
molecular weight of H2O2 or grams. This compound is also known as Hydrogen Peroxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2O2, or 34.01468 grams.
1 grams H2O2 is equal to 0.029399071224542 mole.
1 grams H2O2 to mol = 0.0294 mol
10 grams H2O2 to mol = 0.29399 mol
20 grams H2O2 to mol = 0.58798 mol
30 grams H2O2 to mol = 0.88197 mol
40 grams H2O2 to mol = 1.17596 mol
50 grams H2O2 to mol = 1.46995 mol
100 grams H2O2 to mol = 2.93991 mol
200 grams H2O2 to mol = 5.87981 mol
<u>Answer:</u> The average atomic mass of the element is 6.95 amu
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
We are given:
Mass of isotope 1 = 7.02 amu
Percentage abundance of isotope 1 = 92.6 %
Fractional abundance of isotope 1 = 0.926
Mass of isotope 2 = 6.02 amu
Percentage abundance of isotope 2 = 7.42 %
Fractional abundance of isotope 2 = 0.0742
Putting values in equation 1, we get:
![\text{Average atomic mass of element}=[(7.02\times 0.926)+(6.02\times 0.0742)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D%5B%287.02%5Ctimes%200.926%29%2B%286.02%5Ctimes%200.0742%29%5D)

Hence, the average atomic mass of the element is 6.95 amu