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eimsori [14]
2 years ago
12

Sodium nitrite (NaNO2)reacted with 2−iodooctane to give a mixture of two constitutionally isomeric compounds of molecular formul

a C8H17NO2in a combined yield of 88%. Draw reasonable structures for these two isomers. Click the "draw structure" button to launch the drawing utility. Place the two compounds in the appropriate boxes below. draw structure ... Alkyl nitrite draw structure ... Nitroalkane

Chemistry
2 answers:
finlep [7]2 years ago
3 0

Answer:

The two constitutionally isomeric compounds that result from the reaction between sodium nitrite (NaNO2) and 2−Iodooctane are the following:

lana66690 [7]2 years ago
3 0

Answer:

On the attached picture.

Explanation:

Hello,

In the case, the reaction between 2-iodooctane and sodium nitrite, leads to the formation of an alkyl nitrite and a nitro alkane as shown on the attached picture. Once the reaction began, the salt breaks and the sodium bonds with the iodine from the 2-iodooctane to form sodium iodide, in such a way, a free radical in the second carbon is formed so the NO₂ could bond both as a nitrite and as a nitro radical; therefore, the formed species are octyl 2-nitrite and 2-nitrooctane.

Best regards.

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Write the balanced Ka and Kb reactions for HSO3- in water. Be sure to include the physical states of each species involved in th
Hunter-Best [27]

Answer:

Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]

Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]

Explanation:

An amphoteric substance as HSO₃⁻ is a substance that act as either an acid or a base. When acid:

HSO₃⁻(aq) + H₂O(l) ⇄ H₃O⁺(aq) + SO₃²⁻(aq)

And Ka, the acid dissociation constant is:

<h3>Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]</h3><h3 />

When base:

HSO₃⁻(aq) + H₂O(l) ⇄ OH⁻(aq) + H₂SO₃(aq)

And kb, base dissociation constant is:

<h3>Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]</h3>

6 0
1 year ago
Which of the following would have the most kinetic energy?
cluponka [151]

Answer:

An airplane

Explanation:

An airplane because of its position .

5 0
2 years ago
A. Use average bond energies together with the standard enthalpy of formation of C(g) (718.4 kJ/mol ) to estimate the standard e
Nana76 [90]

Answer:

a. 278.4kJ/mol

b. due to resonance, some energy are released

Explanation:

5 0
2 years ago
at what temperature (inc) would the volume a gas be equal to 45.7L if the volume of gas was 33.9L at 12.4c
vesna_86 [32]

Answer:

The answer to your question is  T1 = 384.7 °K

Explanation:

Data

Volume 1 = V1 = 45.7 l

Temperature 1 = T1 = ?

Volume 2 = V2 = 33.9 l

Temperature 2 = T2 = 12.4°C

To solve this problem use Charles' law

              V1/T1 = V2/T2

                    T1 = V1T2/V2

-Convert temperature to °K

T2 = 12.4 + 273 = 285.4°K

-Substitution

                    T1 = (45.7 x 285.4) / 33.9

-Simplification

                    T1 = 13042.8 / 33.9

-Result

                    T1 = 384.7 °K

7 0
2 years ago
The density of ice is 0.917 g/cm3. How much volume does 52.3 g of ice occupy? Show your work.
mash [69]

Answer:

The answer is

<h2>57.0 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass of ice = 52.3 g

density = 0.917 g/cm³

The volume is

volume =  \frac{52.3}{0.917}  \\  = 57.0338058

We have the final answer as

<h3>57.0 mL</h3>

Hope this helps you

6 0
2 years ago
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