Answer:
Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]
Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]
Explanation:
An amphoteric substance as HSO₃⁻ is a substance that act as either an acid or a base. When acid:
HSO₃⁻(aq) + H₂O(l) ⇄ H₃O⁺(aq) + SO₃²⁻(aq)
And Ka, the acid dissociation constant is:
<h3>Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]</h3><h3 />
When base:
HSO₃⁻(aq) + H₂O(l) ⇄ OH⁻(aq) + H₂SO₃(aq)
And kb, base dissociation constant is:
<h3>Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]</h3>
Answer:
An airplane
Explanation:
An airplane because of its position .
Answer:
a. 278.4kJ/mol
b. due to resonance, some energy are released
Explanation:
Answer:
The answer to your question is T1 = 384.7 °K
Explanation:
Data
Volume 1 = V1 = 45.7 l
Temperature 1 = T1 = ?
Volume 2 = V2 = 33.9 l
Temperature 2 = T2 = 12.4°C
To solve this problem use Charles' law
V1/T1 = V2/T2
T1 = V1T2/V2
-Convert temperature to °K
T2 = 12.4 + 273 = 285.4°K
-Substitution
T1 = (45.7 x 285.4) / 33.9
-Simplification
T1 = 13042.8 / 33.9
-Result
T1 = 384.7 °K
Answer:
The answer is
<h2>57.0 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass of ice = 52.3 g
density = 0.917 g/cm³
The volume is

We have the final answer as
<h3>57.0 mL</h3>
Hope this helps you