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zimovet [89]
2 years ago
6

Kara has 90 lollipops, 36 chocolate bars, and 72 gumballs to put in goody bags for her party. What is the largest number of good

y bags that Kara can make so that each goody bag has the same number of lollipops, the same number of chocolate bars, and the same number of gumballs?
Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
6 0

Answer:

answer : Kara can make 18 goody bags, each containing 5 lollipops, 2 chocolate bars, and 4 gumballs

Step-by-step explanation:

Bad White [126]2 years ago
4 0
The greatest common factor of 90, 36, and 72 = 18

90/18 = 5 lollipops
36/18 = 2 chocolate bars
72/18 = 4 gumballs

answer : Kara can make 18 goody bags, each containing 5 lollipops, 2 chocolate bars, and 4 gumballs
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The answer is b. if you divide 120 and 96, you would get 20 inches.
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Students voted on a school trip. 56 voted for the museum, 86 for the nature center, 172 for the state capital, and 116 for other
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Answer:

a = state capital

b = nature center

c =  museum

d = other

Step-by-step explanation:

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Arthur took out a 20 year loan for $60,000 at an APR of 4.4% compounded monthly. Approximately how munch would save if he paid i
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Monthly payments, P = {R/12*A}/{1- (1+R/12)^-12n}

Where R = APR = 4.4% = 0.044, A = Amount borrowed = $60,000, n = Time the loan will be repaid

For 20 years, n = 20 years
P1 = {0.044/12*60000}/{1- (1+0.044/12)^-12*20} = $376.36

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For 3 years early, n = 17 year
P2 = {0.044/12*60,000}/{1-(1+0.044/12)^-12*17} = $418.22

Total amount to be paid in 17 years, A2 = 418.22*17*12 = $85,316.98

The saving when the loan is paid off 3 year early = A1-A2 = 90,326.30 - 85,316.98 = $5,009.32

Therefore, the approximate amount of savings is A. $4,516.32. This value is lower than the one calculated since the time of repaying the loan does not change. After 17 years, the borrower only clears the remaining amount of the principle amount.
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Emi computes the mean and variance for the population data set 87, 46, 90, 78, and 89. She finds the mean is 78. Her steps for f
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That is,
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A group of kids just finished trick-or-treating. The number of pieces of candy collected by each of the 5 kids
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Answer:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

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And the answer for this case would be :

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Step-by-step explanation:

We have the following data set given:

31, 33, 36, 41, 34

If we want to find the standard deviation we need to find first the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35

Now we can find the sampel deviation with this formula:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808

And the answer for this case would be :

s= 3.81 after round the value

6 0
2 years ago
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