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ira [324]
2 years ago
10

A hydrogen atom with an electron in the first shell (n=1) absorbs ultraviolet light with a wavelength of 1.03×10−7m to what shel

l does the electron jump?
Physics
1 answer:
Evgesh-ka [11]2 years ago
3 0
The Rydberg equation describes the wavelengths of light absorbed or emitted by hydrogen (and ONLY hydrogen) and is: 1/λ = R(1/n₁² - 1/n₂²). Where λ is the wavelength of light, R is the rydberg constant that is equal to 1.097*10⁷ m⁻¹ and n₁ is the initial energy level and n₂ is the final energy level. Thus we solve it for n₂, so we get n₂ = (sqrt(1/n₁² - 1/(λR)))⁻¹, plugging in the numbers, we get n₂ = (sqrt(1/(1)² - 1/((1.03*10⁻⁷)(1.097*10⁷)))⁻¹ = 2.9999..., which is close enough to 3.
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Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2.
GalinKa [24]

Answer:

The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is equal to 2 : 1

Explanation:

Detailed explanation and calculation is shown in the image below

8 0
2 years ago
Someone plans to float a small, totally absorbing sphere 0.500 m above an isotropic point source of light,so that the upward rad
mote1985 [20]

Answer:

468449163762.0812 W

Explanation:

m = Mass = \rhoV

V = Volume =\dfrac{4}{3}\pi r^3

r = Distance of sphere from isotropic point source of light = 0.5 m

R = Radius of sphere = 2 mm

\rho = Density = 19 g/cm³

c = Speed of light = 3\times 10^8\ m/s

A = Area = \pi R^2

I = Intensity = \dfrac{P}{4\pi r^2}

g = Acceleration due to gravity = 9.81 m/s²

Force due to radiation is given by

F=\dfrac{IA}{c}\\\Rightarrow F=\dfrac{\dfrac{P}{4\pi r^2}{\pi R^2}}{c}\\\Rightarrow F=\dfrac{PR^2}{4r^2c}

According to the question

F=mg\\\Rightarrow \dfrac{PR^2}{4r^2c}=\rho \dfrac{4}{3}\pi R^3g\\\Rightarrow P=\dfrac{16r^2\rho c\pi Rg}{3}\\\Rightarrow P=\dfrac{16\times 0.002\times 19000\times \pi\times 0.5^2\times 9.81\times 3\times 10^8}{3}\\\Rightarrow P=468449163762.0812\ W

The power required of the light source is 468449163762.0812 W

4 0
2 years ago
A massive tractor rolls down a country road. in a perfectly inelastic collision, a small sports car runs into the machine from b
Helga [31]
The answer for this change in the magnitude of momentum is the same for both because momentum is always conserved so both vehicles have the identical change. 
So for determining who has the greater change in kinetic energy, momentum (P) = mv so P^2 = m^2 v^2 P^2 / 2m = 1/2 m v^2 = energy So the weightier the mass the smaller the energy change for the same momentum change so in here, the car has a greater change in kinetic energy.
5 0
2 years ago
Read 2 more answers
A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?
guajiro [1.7K]

The correct answer to the question is-  2.2\ \mu C

CALCULATION:

As per the question, the electric field generated by the source charge is 1236  N/C at a distance of 4 m.

Hence , electric field  E =  1236 N/C.

The distance of the point R = 4m

We are asked to calculate the charge possessed by the source.

The electric field produced by a source charge of Q at a distance R is calculated as -

                    Electric field E = \frac{1}{4\pi \epsilon_{0}}\frac{Q}{R^2}

Here, \epsilon_{0} is called the absolute permittivity of the free space.

Hence, the charge of source is calculated as -

                                         Q = E\times 4\pi \epsilon_{0}\times R^2

                                            = 1236\times \frac{1}{9\times 10^9}\times (4)^2\ Coulomb

                                            = 2197.33\times 10^{-9}\ C

                                             = 2.19733\times 10^{-6}\ C

                                             = 2.2\ \mu C

Hence, the charge of source is 2.2\ \mu C

3 0
2 years ago
Read 2 more answers
When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion. Which o
Setler [38]

<u>Answer:</u>

Option: D. Gravity is pulling the crash test dummy in the direction the car is moving.

<u>Explanation: </u>

When a car accelerates from a standing start, the crash test dummy appears to be pressed backward into the seat cushion because the gravity is pulling the crash test dummy in the direction the car is moving.  

Basically when the car is starting, the person inside is in static position and the car is going to move. So it is putting a force on the person to move on the same speed. But as the person is sitting static hence gravity is pulling him behind from moving. Hence, The dummy appears to be pressed backward.

7 0
2 years ago
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