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kolezko [41]
2 years ago
4

Ken wants to build a table and put a border around it. The table and border must have an area of 3,276 square inches. The table

is 36 inches wide and 72 inches long without the border. Which quadratic equation can be used to determine the thickness of the border, x?
4x^2 + 216x + 2,592 = 0
4x^2 + 216x − 684 = 0
2x^2 + 216x − 3,276 = 0
x^2 + 108x + 3,276 = 0
Mathematics
1 answer:
kupik [55]2 years ago
8 0
In this item, the table with the border that is to be constructed is in rectangular form. The area of the rectangle can be computed or solved by multiplying the length and the width. 

Since the given area is that of the table and border. If the thickness of the border is x then, the dimensions are as follow.
        width = 36 + 2x
        length = 72 + 2x

The area of the rectangle is calculated by multiplying the length and width.
           Area = length x width
            Area = (72 + x)(36 + x)
       3276 = 2592 + 108x + x²

Transpose all the terms on one side of the equation,
        <em> x² + 108x - 684 = 0</em>

Thus, the answer is not among the choices but that which is written above. 
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Answer:

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And we can find the real value with the following excel code using the binomial distribution:

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Step-by-step explanation:

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The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

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The probability mass function for the Binomial distribution is given as:

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Where (nCx) means combinatory and it's given by this formula:

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And we want this probability:

P(90< X< 110)

We can use the z score formula given by:

z = \frac{x -\mu}{\sigma}

And replacing we got:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

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"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

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Step-by-step explanation:

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HELLO,

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