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emmasim [6.3K]
2 years ago
4

Calculate the pressure of 0.76 moles of methane that occupies 2800 cm3 at a temperature of 290 K.

Chemistry
2 answers:
Lesechka [4]2 years ago
5 0
Use the ideal gas law:

PV = nRT

so, P = nRT / V

n=0.76
V= 2800 cm^3 = 2.8 L
R = 1/12
T= 290 K

Put the values:

P = \frac{0.76 \times 1 \times 290}{12 \times 2.8}

P = 6.55 atm
katovenus [111]2 years ago
3 0

Answer:

654.12 kPa

Explanation:

Answer for Educere/ Founder's Education

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B

Explanation:

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Which two scenarios illustrate the relationship between pressure and volume as described by Boyle’s law?
Airida [17]

The correct answer is option 2 and 3.

The two scenarios that illustrate the relationship between pressure and volume as described by Boyle’s law are as follows:

2. The volume of an underwater bubble increases as it rises and the pressure decreases.

3. The pressure increases in an inflated plastic bag when the bag is stepped on.

According to Boyle's law, pressure of a gas is inversely proportional to its volume at constant temperature. This means that pressure rises as the volume increases and vice versa.

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2 years ago
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The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0
2 years ago
The successive ionization energies of a certain element are I1= 577.9 kJ/mol, I2 = 1820 kJ/mol, I3= 2750 kJ/mol, I4 = 11,600 kJ/
Maksim231197 [3]

Answer:

Aluminium

Explanation:

Ionization energy is the amount of energy needed to remove an electron from a gaseous atom to form a gaseous ion.

The difference between the third and fourth ionization energies is great. This indicates a group III element which is in the third period.

This element is Aluminium (Al)

6 0
2 years ago
How much volume (in cm3) is gained by a person who gains 11.1 lbs of pure fat?
kirill [66]

The density of human fat is 0.918 g/cm^{3}. The mass of the pure fat is 11.1 lbs.

First convert mass from lb to g as follows:

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Density of a substance is defined as mass per unit volume, thus volume can be calculated as:

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Putting the values,

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Therefore, volume gained by person will be 5484.61 cm^{3}.

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2 years ago
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