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Alexxx [7]
2 years ago
3

john Smith and Susan Jones own a business together. It was agreed that Susan would work 45 hours per week and spend 15 hours wor

king with customers and the remaining time supervising the employees. What fraction of Susan's time is spent working with customers?
Mathematics
2 answers:
xxMikexx [17]2 years ago
4 0
I believe the answer is 15/30= 1/2......hope this helps
Phoenix [80]2 years ago
4 0

Answer: \dfrac{1}{3}

Step-by-step explanation:

Given : The total number of hours Susan work in a week = 45 hours

The total number of hours she need to spend working with customers =  15 hours

Now, the fraction of Susan's time is spent working with customers is given by :-

\dfrac{\text{Hours spent with customers}}{\text{Total hours of working}}\\\\\dfrac{15}{45}=\dfrac{1}{3}

Hence, the fraction of Susan's time is spent working with customers = \dfrac{1}{3}

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Answer:

Step-by-step explanation:

Given that when a basketball player shoots a free​ throw, the odds in favor of his making it are 2020 to 99.

Prob that he shoots a free throw = \frac{99}{2020+99} =0.04672

a) Probability that when this basketball player shoots a free​ throw, he misses it=1-0.04672 = 0.95328

b) When no of throws = 100 average of throws he makes is

Since x no of throws he makes has two outcomes and each trial is independent , X is binomial with n =100 and p = 0.04672

Expected value of throws = np = 4.672

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2 years ago
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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

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8 0
2 years ago
Where to locate the nonnegative abscissa, positive ordinate
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2 years ago
The manager at Jessica's Furniture Store is trying to figure out how much to charge for a couch that just arrived. The couch was
arlik [135]
Answer: $163.85

Explanation:

1) Data:

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mark up: 45%

2) Formula

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Answer: $ 163.85
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