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egoroff_w [7]
2 years ago
6

The perimeter of a rectangular pool is more than 62 meters, and the width is at least 10 meters less than the length. Which syst

em of inequalities represents the possible length in meters, l, and the possible width in meters, w, of the pool?
Mathematics
2 answers:
olganol [36]2 years ago
7 0

Answer:

the answer would be d i just got it right

Step-by-step explanation:

svp [43]2 years ago
5 0

Answer:

2(l+w)>62

w\geq l-10

Step-by-step explanation:

The perimeter p of the rectangular pool with width w and length l is

p=2w+2l

p=2(w+l).

We are told that this perimeter is more than 62 meters; therefore, we have the inequality

2(l+w)> 62

We are also told that width has to be at least 10 meters less than the length; therefore we have

w\geq l-10

Thus the inequalities describing this situation are

2(l+w)>62

w\geq l-10

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Find the average speed of a plane that leaves Bristol at 14.00 and lands in Rome at 17.15.The distance is 1200 miles
horrorfan [7]
It is very important to go through all the details that have been provided in the question. These information's will come in very handy while getting to the solution for the answer. Now let us concentrate on the problem in hand.
Distance between Bristol and Rome that the plane covers = 1200 miles
Starting time of the plane from Bristol = 14:00 hrs
Landing time of the plane in Rome = 17:15 hrs
Then
Total time taken by the plane to travel from Bristol to Rome = 17:15 - 14:00 hours
                                                                                               = 3 .15 hours
So
The average speed of the plane = 1200/3.15 miles per hour
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From the above deduction we can conclude that the average speed of the plane traveling from Bristol to Rome is 380.95 miles per hour.
6 0
2 years ago
Machines A and B always operate independently and at their respective constant rates. When working alone, Machine A can fill a p
pychu [463]

Answer:

The value of x is \frac{10}{3} hours.

Step-by-step explanation:

Machine A = 5 hours

Machine B = x hours

Machine A and B = 2 hours

Using the formula: \frac{T}{A}  + \frac{T}{B} = 1

where:

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A is the time spend by machine A

B is the time spend by machine B

\frac{2}{5}  + \frac{2}{x}  = 1

Let multiply the entire problem by the common denominator (5B)

5x(\frac{2}{5}  + \frac{2}{x} = 1)

2x + 10 = 5x

Collect the like terms

10 = 5x - 2x

10 = 3x

3x = 10

Divide both side by the coefficient of x (3)

\frac{3x}{3}  = \frac{10}{3}

x = \frac{10}{3} hours.

Therefore, Machine B will fill the same lot in \frac{10}{3} hours.

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2 years ago
Riley started selling bracelets. During the first month she sold 400 bracelets at $10 each. She tried raising the price, but for
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I would just divide 400 and 10 and then try to come up with the salary
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Finn bought 2 packs of stickers. Each pack had the same number of stickers. A friend gave him 4 more stickers. Now he has 24 sti
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24-4=20
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10 stickers in each pack
4 0
2 years ago
Read 2 more answers
give an example on an addition problem in which you would and would not group the addends differently to add
Murrr4er [49]
Addends are any of the numbers added together in an equation. 

The only time their grouping would matter would be if there were parentheses used to alter the normal Order of Operations. 

For ex:
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Any addition problem without parentheses can be used for one where the grouping doesn't matter
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