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2 years ago

24 ten thousands + 11 thousands Write the sum in standard form?

Mathematics

2 answers:

Anna35 [415]2 years ago

8 0

Answer:

The sum of the provided numbers in standard form is 251,000.

Step-by-step explanation:

Consider the provided information.

24 ten thousands + 11 thousands

Consider the number 24 ten thousands.

The above number can be written as:

24 ten thousands = 24×10,000

24 ten thousands = 240,000

Now consider the number 11 thousands.

The above number can be written as:

11 thousands = 11×1,000

11 thousands = 11,000

Now add the numbers.

240,000+11,000=251,000

Hence, the sum of the provided numbers in standard form is 251,000.

hodyreva [135]2 years ago

3 0

The standard form is 24,000,011

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Which is a factor of 5x2 − 15x − 20?

Sholpan [36]

Answer:

x= -1, x=4

Step-by-step explanation:

5x²-15x-20

5x²-20x+5x-20=0

5x(x-4) +5(x-4)

(5x+5) (x-4) =0

5x=-5 or x=4

x= -5/5. or x=4

x= -1 or x=4

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2 years ago

Jenna concludes that (4,9) is the solution to the system of these two equations. which of the following justifies her conclusion

nalin [4]

Answer:

a. The point (4,9) appears in both tables

Explanation:

Note: This question can be solved without the need of the tables

A solution of a system of equations is defined as a point (or set of points) that satisfy both equations

This means that, this point should belong to all the equations in the system

Now, a table is used to show a set of points that belong to a certain line

This means that, all vales in the table belong to the line they represent

Since the point (4,9) appears in both tables, therefore, it belongs to both lines and, therefore, is a solution to the system of equations consisting of these two lines

Hope this helps :)

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2 years ago

The base of a solid right pyramid is a regular hexagon with

cupoosta [38]

Answer: Last option.

Step-by-step explanation:

Observe the base of the pyramid, which is a regular hexagon. You can see that there is a right triangle.

The area of the triangle can be calculated with this formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is the height.

You can say that the apothem is the height of the right triangle, then, you need to find the base applying the Pythagorean Theorem:

$(2x)^2=(x\sqrt{3})^2+b^2\\\\b=\sqrt{(2x)^2-(x\sqrt{3})^2} \\\\b=\sqrt{4x^2-3x^2}\\\\b=\sqrt{x^2}\\\\b=x$

Then, the area of the triangle is:

$A_t=\frac{x(x\sqrt{3})}{2}=\frac{x^2\sqrt{3})}{2}$

Since the base of the pyramid is a regular hexagon, then you can multiply by 12 the area of the right triangle calculated above, in order to find the area of the hexagon. Then you get:

$A_h=12(\frac{x^2\sqrt{3})}{2})=6x^2\sqrt{3}\ units^2$