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2 years ago

If you know that the rock fell 4.9 m in 1 s , how far did it drop in the first 0.5 s after you dropped it?

Physics

2 answers:

iren [92.7K]2 years ago

8 0

<u>Answer</u>

1.225 m

<u>Explanation</u>

The formula for getting the distance cover in this case is;

s = ut + 1/2 gt²

Where u⇒intial velocity

t⇒time taken

g ⇒ acceleration due to gravity

But in this case u = 0, t = 1 and s =4.9.

So, the first thin is to calculate the value of g.

S = 1/2 gt²

4.9 = 1/2 g × 1²

g = 4.9 × 2

= 9.8 m/s².

Now calculate the distance after 0.5 s.

S = 1/2 × 9.8 × 0.5²

= 1.225 m

klio [65]2 years ago

7 0

When an object is free-falling, no other force is acting upon it but the gravitational force. Because of this, the equations of motion are simplified. We can determine first the initial velocity:

v = √2gy = √2(9.81)(4.9) = 9.805 m/s

Then, we use this to the equation below:
y = vt + 1/2*at²
y = (9.805)(0.5) + 1/2(9.81)(0.5)²
y = 6.13 m

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A worker stands still on a roof sloped at an angle of 35° above the horizontal. He is prevented from slipping by static friction

aleksley [76]

Answer:

99.63 kg

Explanation:

From the force diagram

N = normal force on the worker from the surface of the roof

f = static frictional force = 560 N

θ = angle of the slope = 35

m = mass of the worker

W = weight of the worker = mg

W Cosθ = Component of the weight of worker perpendicular to the surface of roof

W Sinθ = Component of the weight of worker parallel to the surface of roof

From the force diagram, for the worker not to slip, force equation must be

W Sinθ = f

mg Sinθ = f

m (9.8) Sin35 = 560

m = 99.63 kg

5 0

2 years ago

Jeremy accidently dropped his toy stuffed animal from the balcony of his apartment on the fourth floor. The toy hit the ground a

LekaFEV [45]

According to the second law of motion, force is the product of mass times acceleration. If we were to solve for the force, we would need the acceleration and the mass.

Acceleration was not given in the problem, but we can solve for it by using the velocity and the time because by definition, acceleration is the change in velocity over time.

$a = \frac{vf-vi}{t}$

The initial velocity is 16.0m/s because it is the first recorded time. The final is 0 m/s or the last recorded velocity. The time we will use is 2.0 s because it is the time the change in velocity occurred.

$a = \frac{vf-vi}{t}$
$a = \frac{0m/s-16.0m/s}{2.0s}$
$a = \frac{-16.0m/s}{2.0s}$
$a=-8.0m/ s^{2}$

Now that we have acceleration, we can now solve for the Force. Again Force is the product of mass and acceleration.

$F=ma$
$F=(0.25kg)(-8.0m/ s^{2} )$
$F=-2kg.m/ s^{2} )$ or $-2N$

The force is -2N. Now if you are looking for the magnitude of the force then you can just put 2N.

The negative sign indicates the direction of the force, if it is negative this means that the force applied was in the opposite direction.

4 0

2 years ago

1. Si tengo medio kilo de fruta y te doy un cuarto y tú me das tres cuartos de kilo, ¿cuánto tengo? 2. Si en una carrera te qued

Kipish [7]

Answer:

1. Tienes 1 kg de fruta.

2. Queda por recorrer 1/4 km.

3. Ambos pesan lo mismo.

Explanation:

1. Tienes 1/2 kg y cuando te doy 1/4 te queda:

$m = \frac{1}{2} - \frac{1}{4} = \frac{1}{4}$