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coldgirl [10]
2 years ago
5

A word problem tells you that you have 27.8 moles of carbon dioxide. It asks how much that is in grams of carbon dioxide.

Chemistry
1 answer:
adell [148]2 years ago
5 0
We need to cancel the units

b/c would be equal to 1 to retain the same amount, remember, 1a=a


so
b/c=1mol/44g or 44g/1mol

alrighty
we waant to convert 27.8mols
so therefor a=27.8mol


27.8mol times b/c=D
we want c to be mols and b to be grams so the mols cancel

so thefor c=1mol

it would look like this:
(\frac{27.8mol}{1})*(\frac{44g}{1mol}=\frac{(27.8mol)(44g)}{(1)(1mol)}=
\frac{(27.7)(44g)}{1}


I would write 1 mol of carbon dioxide for C (choice A)
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Answer:

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Explanation:

8 0
2 years ago
Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.
igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, [\text{H}^{+}] = 10^{-\text{pH}}, where [\text{H}^{+}] is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, [\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}.

[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w, where [\text{OH}^{-}] the concentration of hydroxide ions and \text{K}_w is the dissociation constant of water.

\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3} at 0.10 MPa and 25 °C. As a result, [\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}.

5 0
2 years ago
What is the mass of a solution that has a density of 0.775 g/ml and a volume of 50.0ml?
Margarita [4]
Hey there!

D = m / V

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6 0
2 years ago
Please help me double-check my answer: Calculate the molarity of an aqueous solution that contains 36.5g KMnO4 and has a total v
Helen [10]

Answer:

The answer to your question is Molarity = 0.6158, I got the same answer as you.

Explanation:

Data

Molarity = ?

Mass of KMnO₄ = 36.5 g

Total volume = 375 ml

Process

1.- Calculate the Molar mass of KMnO₄

KMnO₄ = (1 x 39.10) + (54.94 x 1) + (16 x 4)

            = 39.10 + 54.94 + 64

            = 158.04 g

2.- Calculate the moles of KMnO₄

                158.04 g of KMnO₄ ------------------- 1 mol

                  36.5 g of KMnO₄ ---------------------  x

                   x = (36.5 x 1) / 158.04

                   x = 0.231 mol

3.- Convert the volume to liters

                  1000 ml -------------------- 1 L

                    375 ml --------------------- x

                     x = (375 x 1)/1000

                    x = 0.375 L

4.- Calculate the Molarity

Molarity = moles / volume

-Substitution

Molarity = 0.231 moles / 0.375 L

Result

Molarity = 0.6158

6 0
2 years ago
Read 2 more answers
Which of the following solutions is a buffer?A) A solution made by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M HCl.B) A s
kumpel [21]

Answer:

D

Explanation:

solution made by mixing 100 mL of 0.100 M HClO and 50 mL of 0.100 M NaOH Can resist pH change when there is little addition of either acid or base, hence it is a buffer solution

7 0
2 years ago
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