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1 year ago

What's green and fluffy and comes from outer space? I have the answer I just need to know how to graph it

Mathematics

2 answers:

BaLLatris [955]1 year ago

8 0

What’s green and fluffy and comes from outer space?

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1 . 2x – 4y = 8

Rewriting the standard form linear equation into slope intercept form.

-4y = -2x + 8

Dividing both sides by -4.

y = (-2/-4)x + 8/-4

y = (1/2)x - 2

The best match is A and 23.

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2. 2x + 8y = - 64

Rewriting the standard form linear equation into slope intercept form.

8y = - 2x - 64

Dividing both sides by 8.

y = (-2/8)x - 64/8

y = -1/4 x - 8

The best match is N and 19.

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3. -2x + 4y = 8

Rewriting the standard form linear equation into slope intercept form.

4y = 2x + 8

Dividing both sides by 4

y = (2/4)x + 8/4

y = 1/2 x + 2

The best match is M and 4.

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4. 3x + 5y = -15

Rewriting the standard form linear equation into slope intercept form.

5y = - 3x - 15

Dividing both sides by 5.

y = (-3/5)x - 15/5

y = -3/5 x - 3

The best match is M and 15.

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5. 12x - 3y = 3

Rewriting the standard form linear equation into slope intercept form.

-3y = -12x + 3

Dividing both sides by -3.

y = -12/-3 x + 3/-3

y = 4x - 1

The best match is L and 16.

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6. y = - 8

In this case the slope is zero. Which means the rise is zero and run can be anything greater than 1. This will make a horizontal line parallel to the y-axis at the point (0 , -8).

The best match is L and 11.

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7. x + 3y = 18

Rewriting the standard form linear equation into slope intercept form.

3y = -x + 18

Dividing both sides by 3.

y = -1/3 x + 18/3

y = -1/3 x + 6

The best match is T and 2.

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8. -4x + 6y = -54

Rewriting the standard form linear equation into slope intercept form.

6y = - 4x - 54

Dividing both sides by 6.

y = -4/6 x - 54/6

y = -2/3 x - 9

The best match is I and 5.

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9. 4x - y = - 8

Rewriting the standard form linear equation into slope intercept form.

-y = - 4x - 8

Dividing both sides by -1.

y = -4/-1 x - 8/-1

y = 4 x + 8

The best match is B and 22.

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10. 2x - 10y = 20

Rewriting the standard form linear equation into slope intercept form.

-10y = -2x + 20

Dividing both sides by -10.

y = -2/-10 x + 20/-10

y = 1/5 x - 2

The best match is O and 24.

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11. 6x + 9y = 9

Rewriting the standard form linear equation into slope intercept form.

9y = -6x + 9

Dividing both sides by 9.

y = -6/9 x + 9/9

y = -2/3 x + 1

The best match is E and 7.

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12. 5x - 2y = 12

Rewriting the standard form linear equation into slope intercept form.

-2y = -5x + 12

Dividing both sides by -2.

y = -5/-2 x + 12/-2

y = 5/2 x - 6

The best match is A and 8.

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13. 8x + 4y = 40

Rewriting the standard form linear equation into slope intercept form.

4y = -8x + 40

Dividing both sides by 4.

y = -8/4 x + 40/4

y = -2 x + 10

The best match is A and 12.

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14. x + 3y = 27

Rewriting the standard form linear equation into slope intercept form.

3y = -x + 27

Dividing both sides by 3.

y = -1/3 x + 27/3

y = -1/3 x + 9

The best match is W and 2.

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ANSWERING TEXT :

A M A R T I A N M E L L O W

23 15 8 22 2 5 12 19 4 7 11 16 24 18

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satela [25.4K]1 year ago

6 0

The <em><u>correct answer</u></em> is:

To graph each of these equations, we will find the x- and y-intercept of each. To find the x-intercept, we replace y with 0 and solve. To find the y-intercept, replace x with 0 and solve.

For 2x-4y=8:

x-intercept:

2x-4(0)=8; 2x-0=8; 2x=8; x=4

y-intercept:

2(0)-4y=8; 0-4y=8; -4y=8; y=-2

Plot these intercepts and draw a line between them.

For 2x+8y=-64:

x-intercept:

2x+8(0)=-64; 2x+0=-64; 2x=-64; x=-32

y-intercept:

2(0)+8y=-64; 0+8y=-64; 8y=-64; y=-8

Plot the intercepts and draw a line between them.

For -2x+4y=8:

x-intercept:

-2x+4(0)=8; -2x+0=8; -2x=8; x=-4

y-intercept:

-2(0)+4y=8; 0+4y=8; 4y=8; y=2

Plot the intercepts and draw a line between them.

For 3x+5y=-15:

x-intercept:

3x+5(0)=-15; 3x+0=-15; 3x=-15; x=-5

y-intercept:

3(0)+5y=-15; 0+5y=-15; 5y=-15; y=-3

Plot the intercepts and draw a line between them.

For 12x-3y=3:

x-intercept:

12x-3(0)=3; 12x-0=3; 12x=3; x=3/12=0.25

y-intercept:

12(0)-3y=3; 0-3y=3; -3y=3; y=-1

Plot the intercepts and draw a line between them.

For y=-8, draw a straight horizontal line at -8.

For x+3y=18:

x-intercept:

x+3(0)=18; x+0=18; x=18

0+3y=18; 3y=18; y=6

Plot the intercepts and draw a line between them.

For -4x+6y=-54:

x-intercept:

-4x+6(0)=-54; -4x+0=-54; -4x=-54; x=13.5

y-intercept:

-4(0)+6y=-54; 0+6y=-54; 6y=-54; y=-9

Plot the intercepts and draw a line between them.

For 4x-y=-8:

x-intercept:

4x-0=-8; 4x=-8; x=-2

y-intercept:

4(0)-y=-8; 0-y=-8; -y=-8; y=8

Plot the intercepts and draw a line between them.

For 2x-10y=20:

x-intercept:

2x-10(0)=20; 2x-0=20; 2x=20; x=10

y-intercept:

2(0)-10y=20; 0-10y=20; -10y=20; y=-2

Plot the intercepts and draw a line between them.

For 6x+9y=9:

x-intercept:

6x+9(0)=9; 6x+0=9; 6x=9; x=1.5

y-intercept:

6(0)+9y=9; 0+9y=9; 9y=9; y=1

Plot the intercepts and draw a line betwen them.

For 5x-2y=12:

x-intercept:

5x-2(0)=12; 5x-0=12; 5x=12; x=2.4

y-intercept:

5(0)-2y=12; 0-2y=12; -2y=12; y=-6

Plot the intercepts and draw a line between them.

For 8x+4y=40:

x-intercept:

8x+4(0)=40; 8x+0=40; 8x=40; x=5

y-intercept:

8(0)+4y=40; 0+4y=40; 4y=40; y=10

Plot the intercepts and draw a line between them.

For x+3y=27:

x-intercept:

x+3(0)=27; x+0=27; x=27

y-intercept:

0+3y=27; 3y=27; y=9

Plot the intercepts and draw a line between them.

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Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,

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Emily wants to hang a painting in a gallery. The painting and frame must have an area of 31 square feet. The painting is 5 feet

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Suppose that Kevin can choose to get home from work by car or bus. When he chooses to get home by car, he arrives home after 7 p

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The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = 0.838

Step-by-step explanation:

Let the probability that Kevin arrives home after 7 pm be P(L)

Probability that Kevin uses the bus = P(B)

Probability that Kevin uses the car = P(C)

Probability of arriving home after 7 pm if the car was taken = P(L|C) = 4% = 0.04

Probability of arriving home after 7 pm if the bus was taken = P(L|B) = 15% = 0.15

The bus is cheaper, So, he uses the bus 58% of the time.

P(B) = 58% = 0.58

P(C) = P(B') = 1 - P(B) = 1 - 0.58 = 0.42

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm = P(B|L)

The conditional probability P(A|B) is given mathematically as

P(A|B) = P(A n B) ÷ P(B)

Hence, the required probability, P(B|L) is given as

P(B|L) = P(B n L) ÷ P(L)

But we do not have any of P(B n L) and P(L)

Although, we can obtain these probabilities from the already given probabilities

P(L|C) = 0.04

P(L|B) = 0.15

P(B) = 0.58

P(C) = 0.42

P(L|C) = P(L n C) ÷ P(C)

P(L n C) = P(L|C) × P(C) = 0.04 × 0.42 = 0.0168

P(L|B) = P(L n B) ÷ P(B)

P(L n B) = P(L|B) × P(B) = 0.15 × 0.58 = 0.087

P(L) = P(L n C) + P(L n B) = 0.0168 + 0.087 = 0.1038 (Since the bus and the car are the two only options)

The approximate probability that Kevin chose to get home from work by bus, given that he arrived home after 7 pm

= P(B|L) = P(B n L) ÷ P(L)

P(B n L) = P(L n B) = 0.087

P(L) = 0.1038

P(B|L) = (0.087/0.1038) = 0.838150289 = 0.838

Hope this Helps!!!

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