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padilas [110]
2 years ago
15

Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 2

0 grams, and its density is 7.87 g/cm3. What’s the larger cube’s volume?
Physics
2 answers:
alexandr402 [8]2 years ago
8 0

Answer:

5.08 but if it asks that it needs to be rounded to the nearest whole number, then the answer would be 5

Explanation:

I got this wrong because I was supposed to round it :( Don't my mistake guys

lbvjy [14]2 years ago
6 0
Density = mass/volume, volume = mass/density.
Since the mass of the small cube equals 20 and the mass of the large cube is double it would be 40.
Now plug in volume = 40 g/(7.87 g/cm^3).
Thus giving you a volume 5.08 cm^3
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Your eye is designed to work in air. Surrounding it with water impairs its ability to form images. Consequently, scuba divers we
grin007 [14]

Answer:

Check the explanation

Explanation:

A) There are two important angles within the plastic: the angle immediately after the first refraction (the water/plastic interface) and the angle immediately before the second refraction (the plastic/air interface).

To find out how they relate, draw a picture with the path the light follows in the plastic and the normal to both surfaces.

Once you have labeled both angles, keep in mind that the surfaces are parallel, and thus their normal are parallel lines. An important theorem from geometry will give you the relationship between the angles.

Using Snell's Law,   θa = asin[(nw/na)*sin(θw)]

B) D = l/tan(θw)

C) D = l/θw

D) d/D = na/nw

8 0
2 years ago
A rectangular beam 10 cm wide, is subjected to a maximum shear force of 50000 N, the corresponding maximum shear stress being 3
nika2105 [10]

Answer:

Option B is the correct answer.

Explanation:

Shear stress is the ratio of shear force to area.

We have

       Shear stress = 3 N/mm² = 3 x 10⁶ N/m²

       Area = Area of rectangle = 10 x 10⁻² x d = 0.1d

       Shear force = 50000 N

Substituting

        \texttt{Shear stress}=\frac{\texttt{Shear force}}{\texttt{Area}}\\\\3\times 10^6=\frac{50000}{0.1d}\\\\d=0.1667m=16.67cm

Width of beam = 16.67 cm

Option B is the correct answer.

6 0
2 years ago
Two identical metal balls are rolling without slipping along a horizontal surface with speed V. Each ball encounters a hill ('tw
Anastaziya [24]

Answer:

The angular velocity of Ball A will be greater than the angular velocity of Ball B when they reach the top of the hill.

Explanation:

Angular velocity can be defined as how fast an object rotates relative to a given point or frame of reference.

The question said the hill encountered by Ball A is frictionless, so Ball A will continue to rotate at the same rate it started with even when it reached the top of the hill.

Ball B on the other hand rolls without slipping over its hill, i.e there's friction to slow down its rotational motion which thus reduces how fast Ball B will rotate at the top of the hill

3 0
2 years ago
A rock of mass m is thrown horizontally off a building from a height h. the speed of the rock as it leaves the thrower's hand at
Stells [14]
The correct answer is <span>3) K_f =  \frac{1}{2}mv_0^2 + mgh.
</span>
In fact, the total energy of the rock when it <span>leaves the thrower's hand is the sum of the gravitational potential energy U and of the initial kinetic energy K:
</span>E=U_i+K_i=mgh +  \frac{1}{2}mv_0^2
<span>As the rock falls down, its height h from the ground decreases, eventually reaching zero just before hitting the ground. This means that U, the potential energy just before hitting the ground, is zero, and the total final energy is just kinetic energy: 
</span>E=K_f<span>
But for the law of conservation of energy, the total final energy must be equal to the tinitial energy, so E is always the same. Therefore, the final kinetic energy must be
</span>K_f = mgh +  \frac{1}{2}mv_0^2<span>
</span>

7 0
2 years ago
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 cans, 0.355 - l each,
Alona [7]
Flow rate = 220*0.355 l/m = 78.1 l/min = 1.3 l/s = 0.0013 m^3/s

Point 2:
A2= 8 cm^2 = 0.0008 m^2
V2 = Flow rate/A2 = 0.0013/0.0008 = 1.625 m/s
P1 = 152 kPa = 152000 Pa

Point 1:
A1 = 2 cm^2 = 0.0002 m^2
V1 = Flow rate/A1 = 0.0013/0.0002 = 6.5 m/s
P1 = ?
Height = 1.35 m

Applying Bernoulli principle;
P2+1/2*V2^2/density = P1+1/2*V1^2/density +density*gravitational acceleration*height
=>152000+0.5*1.625^2*1000=P1+0.5*6.5^2*1000+1000*9.81*1.35
=> 153320.31 = P1 + 34368.5
=> P1 = 1533210.31-34368.5 = 118951.81 Pa = 118.95 kPa
3 0
2 years ago
Read 2 more answers
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