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2 years ago

Which word equation shows lithium oxide being formed from the reaction between oxygen and lithium

Chemistry

2 answers:

Paraphin [41]2 years ago

5 0

Answer : The balanced reaction is,

$2Li(s)+\frac{1}{2}O_2(g)\rightarrow Li_2O(s)$

Explanation :

Metal oxide is formed by the burning of metal in presence of air.

General reaction is,

$Metal+Oxygen\rightarrow \text{ Metal oxide}$

So, when lithium react with oxygen then they will form lithium oxide.

The balanced reaction is,

$2Li(s)+\frac{1}{2}O_2(g)\rightarrow Li_2O(s)$

inn [45]2 years ago

3 0

Answer: The word equation is given below.

Explanation:

Word equation is defined as the chemical equation in which chemical substances are written in words rather than in their chemical formulas.

So, the word equation for the reaction of lithium and oxygen to form lithium oxide is:

$\text{Lithium + Oxygen}\rightarrow \text{Lithium Oxide}$

The balanced chemical equation with their chemical formulas is given as:

$4Li(s)+O_2(g)\rightarrow 2Li_2O(s)$

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Table salt (NaCl) is a compound. Every molecule of table salt has the same properties as every other molecule of table salt beca

Fiesta28 [93]

Table salt (NaCl) is a compound. Every molecule of table salt has the same properties as every other molecule of table salt because they all have one sodium (Na) atom and one chlorine (Cl) atom. This is referred to as fixed composition.

Hope this helps! Please correct me if I'm wrong :)

4 0

2 years ago

Hafnium has six naturally occurring isotopes: 0.16% of 174Hf, with an atomic weight of 173.940 amu; 5.26% of 176Hf, with an atom

ser-zykov [4K]

Answer:

177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

Second isotope =175.941amu

Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

Average atomic weight of Hafnium= sum of all the atomic weights of the isotopes/ Total occuring isotopes

Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

Average atomic weight= 1063.661amu /6 = 177.2768333amu

= 177.277amu to 3 decimal places.

6 0

2 years ago

Convert 2.0 M of Phenobarbital sodium (MW: 254 g/mole) solution in water into % w/v and ratio strengths.

Travka [436]

Answer:

The concentration is 50,8 % w/v and radio strengths = 1,96.

Explanation:

Phenobarbital sodium is a medication that could treat insomnia, for example.

2,0 M of Phenobarbital sodium means 2 moles in 1L.

The concentration units in this case are %w/v that means 1g in 100 mL and ratio strengths that means 1g in r mL. Thus, 2 moles must be converted in grams with molar weight -254 g/mole- and liters to mililiters -1 L are 1000mL-. So:

2 moles × $\frac{254 g}{1 mole}$ = 508 g of Phenobarbital sodium.

1 L × $\frac{1000 mL}{ 1 L}$ = 1000 mL of solution

Thus, % w/v is:

$\frac{508 g}{1000 mL}$ × 100 = 50,8 % w/v

And radio strengths:

$\frac{1000 mL}{508 g}$ = 1,96. Thus, you have 1 g in 1,96 mL

I hope it helps!

5 0

2 years ago

Based on the products obtained, rank the functional groups (acetamido, amino, and methoxy) in order of increasing ability to act

I am Lyosha [343]

Answer:

Amino >Methoxy > Acetamido

Explanation:

Bromination is of aromatic ring is an electrophilic substitution reaction. The attached functional group to the benzene ring activates or deactivate the aromatic ring towards electrophilic substitution reaction.

The functional group which donates electron to the benzene ring through inductive effect or resonance effect activates the ring towards electrophilic substitution reaction.

The functional group which withdraws electron to the benzene ring through inductive effect or resonance effect deactivates the ring towards electrophilic substitution reaction.

Among given, methoxy and amino are electron donating group. Amino group are stronger electron donating group than methoxy group. Acetamido group because of presence of carbonyl group becomes electron withdrawing group.

Therefore, decreasing order will be as follows:

Amino >Methoxy > Acetamido

7 0

2 years ago

For which of the following properties does sodium have a larger value than rubidium? Select all that apply.

Doss [256]

Answer:

Ionization energy

Electronegativity

Explanation:

-due to its smaller ionic radius....the electron in the outter most shell tends to expierence a stronger nuclear attraction...which makes it harder to remove the electron from the sodium atom

-Rubidium has lesser ionization energy because its (i) affected by its larger ionic radius which tends to lessen the nuclear attraction ...hence making it easier to remove the electron...(ii)and also by the screening effect done by the inner shells, which also tends to lessen the nuclear attraction.

Sodium has a higher electronegativity than rubidium;

Electronegativity is the charge density of electrons in an atom...in which its high when the atomic radius is smaller...

So hence due to the sodium atomic radius being smaller...it tends to have a higher charge density than rubidium....which then gives it a higher electronegativity value

4 0

2 years ago