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2 years ago

Giselle used the table to predict the cost of one year of college.

2 answers:

8 0

Giselle should put at least $600 in an interest bearing savings account. She has 4 years to save money for college and although she predicts she may receive a $4,000 grant, that does not mean she will. Her expenses are well over $4,000 and if she saves $600 a month for 48 months she will have $28,800 saved without the added interest she will be earning monthly.

Marat540 [252]2 years ago

5 0

Answer: $600

Explanation:

Total Estimated Cost is given by

$12,450 + $10,125 + $2,600 + $2,250 + $1,250

= $28,675

Allowable time to save = 4 years

= 4 * 12 months

= 48 months

Hence,

The amount to save per month is given by

$28,675 ÷ 48

= $597.40

Therefore,

She should save a minimum of $600 monthly. With this, she will be able to pay for her college in one year.

Note : the $4,000 grant was excluded from the calculation because it's a prediction.

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Gabe's Granola Bars had coffee mugs created with their company logo and passed them out on a busy Saturday at a popular grocery

kozerog [31]

Answer:

It would be an example of advertising.

Explanation:

This is because Gabe's Granola Bars are giving coffee mugs with their logo at a grocery store, not their own location.

I hope this helped!

5 0

2 years ago

Read 2 more answers

An appliance dealer must decide how many (if any) new microwave ovens to order for next month. The ovens cost $220 and sell for

Vlada [557]

Answer:

Explanation:

Order 0: we have unsold items for which the return is -25

return is -25*(.4*1+.2*2+.1*3) = -25*1.1 = $-27.50

Order 1: we have to sell at a discount if no orders, otherwise sell 1, and unsold items if demand 2 or 3

return is .3*(1/2*300-220) + (1-.3)*(300-220) + -.25*(.2*1+.1*2) = .3*-70+.7*80+-25*(.4) =

-21 + 56 - 10 = $25

Order 2: we have to sell at a discount if 0 or 1 orders, sell 1 or 2, and unsold items if demand 3

return is (.3*2+.4*1)*(1/2*300-220)+(.4*1+(.2+.1)*2)*(300-220)+-25*.1 =1*-70+1*80-25*.1 =

-70 + 80 - 2.5 = $7.50

Order 3:

return is (.3*3+.4*2+.2*1)*(1/2*300-220)+(.4*1+.2*2+.1*3)*(300-220) = 1.9*-70 + 1.1*80 =

-133 + 88 = -$45

Order 1, with a return of $25, as this is the highest return.

b) If we had a perfect information, we would never pay a penalty for underordering or suffer a discounted return from over-ordering

(.4*1+.2*2+.1*3)*(300-220) = 1.1*80 = $88

Then, the value of perfect information is $88 - $25 = $63

c) P(D=0|F) = P(F|D=0)*P(D=0)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.1*.3/(.1*.3+.2*.4+.3*.2+.9*.1)=.03/.26 = 3/26

P(D=1|F) = P(F|D=1)*P(D=1)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.2.4/(.1*.3+.2*.4+.3*.2+.9*.1)=.08/.26 = 4/13

P(D=2|F) = P(F|D=2)*P(D=2)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.3*.2/(.1*.3+.2*.4+.3*.2+.9*.1)=.06/.26 = 3/13

P(D=3|F) = P(F|D=3)*P(D=3)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.9*.1/(.1*.3+.2*.4+.3*.2+.9*.1)=.09/.26 = 9/26

P(D=0|U) = P(U|D=0)*P(0)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.8*.3/(.8*.3+.3*.4+.1*.2+.1*.1)=.24/.39 = 8/13

P(D=1|U) = P(U|D=1)*P(1)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.3*.4/(.8*.3+.3*.4+.1*.2+.1*.1)=.12/.39 = 4/13

P(D=2|U) = P(U|D=`)*P(`)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.2/(.8*.3+.3*.4+.1*.2+.1*.1)=.02/.39 = 2/39

P(D=3|U) = P(U|D=3)*P(3)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.1/(.8*.3+.3*.4+.1*.2+.1*.1)=.01/.39 = 1/39

P(N|D=0 = 1-.1-.8 = .1

P(N|D=1) = 1 - .2 - .3 = .5

P(N|D=2) = 1 - .3 - .1 = .6

P(N|D=3) = 1 - .9 - .1 = 0

P(D=0|N) = P(N|D=0)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))=.1*.3/(.1*.3+.5*.4+.6*.2+.0*.1)= .03/.35 = 3/35

P(D=1|N) = P(N|D=1)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .5*.4/(.1*.3+.5*.4+.6*.2+.0*.1)= .20/.35 = 4/7

P(D=2|N) = P(N|D=2)*P(D=2)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .6*.2/(.1*.3+.5*.4+.6*.2+.0*.1)= .12/.35 = 12/35

P(D=3|N) = 0

If the result of the survey is an F, we have

P(D=0|F) = 3/26

P(D=1|F) = 4/13

P(D=2|F) = 3/13

P(D=3|F) = 9/26

If the order is 0, the return is -25*(1*4/13+2*3/13+3*9/26) = -25*47/26 = -1175/26 = -$45.19

If the order is 1, the return is 3/26*-70+(1-3/26)*80+-25*(1*3/13+2*9/26) = 515/13 = $39.62

If the order is 2, the return is (3/26*2+4/13)*-70+(1*4/13+2*(3/13+9/26))*80 + -25*9/26 =

1835/26 = $70.58

If the order is 3, the return is (3/26*3+4/13*2+3/13)*-70+(1*4/13+2*3/13+3*9/26)*80 =

795/13 = $61.15

We should order 2.

P(D=0|U) = 8/13

P(D=1|U) = 4/13

P(D=2|U) = 2/39

P(D=3|U) = 1/39

If we order 0, the return is (4/13*1+2/39*2+1/39*3)*-25 = -475/39 = -$12.18

If the order is 1, the return is 8/13*-70+(1-8/13)*80+-25*(1*2/39+2*1/39) =-580/39= -14.87

If the order is 2, the return is (8/13*2+4/13)*-70+(1*4/13+2*(2/39+1/39))*80 + -25*1/39 =

-2785/39= -$71.41

If the order is 3, the return is (8/13*3+4/13*2+2/39*1)*-70+(1*4/13+2*2/39+3*1/39)*80 =

-1780/13 = -$136.92

Order 0

P(D=0|N) = 3/35

P(D=1|N) = 4/7

P(D=2|N) = 12/35

P(D=3|N) = 0

If we order 0, the return is (4/7*1+12/35*2)*-25 = -220/7 = -$31.43

If the order is 1, the return is 3/35*-70+(1-3/35)*80+-25*(1*12/35) = 410/7 = $58.57

If the order is 2, the return is (3/35*2+4/7)*-70+(1*4/7+2*12/35)*80 = 340/7 = $48.57

We don't order 3, as the probability of 3 is 0

we order 1

We order 2 if there is an F, 0 if there is an N, and 1 if there is a U.

d) P(F) = .26

P(N) = .39

P(U) = .35

Then, the expected return is .26*1835/26 +-475/39*.39 + 410/7*.35 = $34.10

Since we make $25 if we just take 1, we should pay up to $34.10-$25 = $9.10 for the survey.

5 0

2 years ago

Schrute Farm Sales buys portable generators for $470 and sells them for $720 He pays a sales commission of 5% of sales revenue t

ad-work [718]

Answer:

The correct answer is A.

Explanation:

Giving the following information:

Schrute Farm Sales buys portable generators for $470 and sells them for $720 He pays a sales commission of 5% of sales revenue to his sales staff. Mr. Schrute pays $7,000 a month rent for his store and also pays $1,700 a month to his staff in addition to the commissions. Mr. Schrute sold 500 generators in June.

Revenue= 720*500= $360,000

Cost of goods sold= 470*500= 235,000 (-)

Sales commision= 0.05*360,000= 18,000 (-)

Contribution Margin= 107,000

Rent= 7,000 (-)

Fixed sales comission= 1,700 (-)

Operating income= $98,300

8 0

1 year ago

Unearned Income of Minor Children and Certain Students (LO 6.4) Brian and Kim have a 12-year-old child, Stan. For 2019, Brian an

antiseptic1488 [7]

Answer:

Answer for the question : Stan's tax for 2018 =105+240 = $345.

"Unearned Income of Minor Children and Certain Students (LO 6.4) Brian and Kim have a 12-year-old child, Stan. For 2019, Brian and Kim have taxable income of $52,000, and Stan has interest income of $4,500. No election is made to include Stan's income on Brian and Kim's return. Click here to access the income tax rate schedules and the trust and estate tax rate schedules.a. For purposes of the tax on a child's unearned income, calculate Stan's taxable income.b.Calculate Stan's earned taxable income."

is explained in the attachment.

Explanation:

3 0

1 year ago

Show the total cost expression and calculate the EOQ for an item with holding cost rate 18%, unit cost $8.00, annual demand of 4

torisob [31]

Answer:

Total cost = Total ordering cost + Total holding cost

Total cost = DCo + QH

Q 2

Where

D = Annual demand

Co = Ordering cost per order

Q = EOQ

H = Holding cost per item per annum

D = 40,000 units

Co = $48

H = 18% x $8.00 = $1.44

EOQ = √2DCo

EOQ = √2 x 40,000 x $48

$1.44

EOQ = 1,633 units

Explanation:

EOQ equals 2 multiplied by annual demand and ordering cost divided by holding cost per item per annum. The holding cost per item per annum is calculated as holding cost rate multiplied by unit cost.

7 0

2 years ago