Answer
The answer is C. Trina is not correct because the two sides of the equation are equivalent.
Step-by-step explanation:
1. solve for x
-8(x - 4) + 2x = -4(x - 8) -2x
-8x + 32 + 2x = -4x + 32 -2x
-6x + 32 = - 6x + 32
0 = 0
This equation has infinite solutions, any rational number fits as solution for x in this equation. And as we can see both sides of it are equivalent.
Therefore, the correct answer is C. Trina is not correct because the two sides of the equation are equivalent.
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<u><em>Hope This Helps :p</em></u>
Answer:
The answer is below
Step-by-step explanation:
The volume of a cuboid is the product of its length, height and breadth. It is given by:
Volume = length × breadth × height
Since the volume is given by the expression 12y² + 8y - 20. That is:
Volume = 12y² + 8y - 20 = 4(3y² + 2y - 5) = 4(3y² + 5y - 3y -5) = 4[y(3y + 5) -1(3y + 5)]
Volume = 4(y-1)(3y+5)
Or
Volume = 12y² + 8y - 20 = 2(6y² +4y - 10) = 2(6y² + 10y - 6y -10) = 2[y(6y + 10) -1(6y + 10)]
Volume = 2(y-1)(6y+10)
Therefore the dimensions of the cuboid are either 4, y-1 and 3y+5 or 2, y-1 and 6y+10
Let L be the length of one side of Kamila's bedroom (since her bedroom is square, the area would be L x L). Then the width of her living room is 1.25L. So:
18*1.25L=2.5(L)²
22.5L=2.5L²
L=22.5/2.5=9
Kamila's bedroom is 9'x9'; her living room is 11.25'x18'. ☺☺☺☺
Answer: 1.5 meters
Step-by-step explanation:
Given: A lake near the Arctic Circle is covered by a sheet of ice during the cold winter months. S
S(t) models the ice sheet's thickness (in meters) as a function of time t (in weeks) 
if we put x=0, then

So 4 meters is the initial thickness
To find the thickness after 6 weeks, put x=6 we get

Decrease in thickness every 6 weeks= 
Answer:
The <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.
Step-by-step explanation:
The confidence interval formula for mean difference for a paired data is as follows:

Here,
= sample mean of the difference,
= sample standard deviation of the difference,
<em>n </em>= sample size (both samples are of same size).
= critical value of <em>t</em>
(<em>n</em> - 1) = degrees of freedom
The information provided is:
<em>n</em> = 5
Confidence level = 95%
The critical value of <em>t</em> is:



*Use a <em>t</em>-table for the critical value of <em>t</em>.
Thus, the <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.