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juin [17]
1 year ago
8

How do you do this?

Mathematics
1 answer:
Ray Of Light [21]1 year ago
7 0
Thats a hardie gooks b
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PLZZZZZZ HELP WILL GIVE BRAINLEST
jonny [76]

−7⋅(−3)⋅(−9)⋅(−3)

21 * -9 * -3

-189 * -3

567

Choice D

4 0
2 years ago
Read 2 more answers
What is the zero in the quadratic function f(x)= 9x^2-54x-19?
Alex17521 [72]

Answer:

6.33... and 0.333...

Step-by-step explanation:

The quadratic formula is


x=\frac{-b+\sqrt{b^2-4ac} }{2a}.


It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions.  Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-54)+/-\sqrt{(-54)^2-4(9)(-19)} }{2(9)}\\x=\frac{54+/-\sqrt{2916+684} }{18}

We will now solve for the plus and the minus.

The plus,,,

x=\frac{54+\sqrt{3600}}{18}\\x=\frac{54+60}{18}\\x=\frac{114}{18}\\x=6.3

and the minus...

x=\frac{54-\sqrt{3600}}{18}\\x=\frac{54-60}{18}\\x=\frac{-6}{18}\\x=-0.333...

8 0
2 years ago
B, C and D are points on a circle, centre O. AB and AD are tangents to the circle. Angle BCD=x Find an expression for the size o
stealth61 [152]

Answer:

where the point B lie ,first say point B where lie

3 0
2 years ago
People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the
Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by  

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

6 0
2 years ago
A veterinarian needs to know an animal's weight in kilograms.If 20 pounds is about 9 kilograms and dog weighs 30 pounds,use a ra
Lesechka [4]

Answer:

Using the ratio table the dogs weight is:

30 pounds = 13.5 kilograms

Step-by-step explanation:

For this case we have the following conversion:

20 pounds = 9 kilograms

To use the table what we must do is find another relationship that allows us to find the weight in kilograms for 30 pounds.

For example, half the weight in pounds is half the weight in kilograms.

Therefore, the given conversion is:

10 pounds = 4.5 kilograms

So, for 30 pounds, we multiply this last ratio obtained by three on both sides:

30 pounds = 13.5 kilograms

Then, the table is:

Pounds 10 20 30

7 0
1 year ago
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