answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mestny [16]
2 years ago
7

Aqueous potassium iodate and potassium iodide react in the presence of dilute hydrochloric acid, as shown below. kio3(aq) + 5ki(

aq) + 6hcl(aq) ⟶ 3i2(aq) + 6kcl(aq) + 3h2o(l) what mass (in g) of iodine is formed when 12.1 ml of 0.097 m kio3 solution reacts with 30.8 ml of 0.017 m ki solution in the presence of excess hcl? enter to 4 decimal places.
Chemistry
1 answer:
Musya8 [376]2 years ago
4 0
<span>0.0797 g Looking at the formula, 1 mole of KIO3 and 5 moles of KI will react and produce moles of iodine molecules or 6 moles of iodine atoms. So first, determine the number of moles of KIO3 and KI provided moles KIO3 = 0.0121 * 0.097 = 0.0011737 mol moles KI = 0.0308 * 0.017 = 0.0005236 mol The limiting reactant is KI at 0.0005236 mol so divide by 5 and multiply by 6 to get the number of moles of iodine atoms. 0.0005236 / 5 * 6 = 0.00062832 mol Lookup the atomic weight of iodine which is 126.90447 And multiply that by the number of moles of iodine produced 126.90447 g/mol * 0.00062832 mol = 0.079736617 g Rounding to 4 decimal places gives 0.0797 g</span>
You might be interested in
Which of these is a base? a-vinegar b-ammonia c-HCl d- HNO3
Lady_Fox [76]
B- ammonia. ammonia has a pH level of about 11, and anything higher than 7  is more basic and anything less than 7 is more acidic. 7 is considered neutral.
6 0
2 years ago
Read 2 more answers
compare and contrast melting 10 kg of ice freezing 1 kg of water. be sure to address temperature,heat flow, and thermal energy
liraira [26]
<span>Melting is an endothermic process (i.e. it absorbs heat), whereas freezing is an exothermic process (i.e. it releases heat, or can be thought of, albeit incorrectly from a thermodynamics standpoint, as "absorbing cold"). The standard enthalpy of fusion of water can be used for both scenarios, but standard enthalpy is in units of energy/mass, so 10 times as much energy will be absorbed in the former scenario (melting 10 kg of ice) than what will be absorbed in the latter scenario (freezing 1 kg of water). For both processes, assuming the water is pure and at standard atmospheric pressure, and the entire mass remains at thermal equilibrium, the temperature of both the solid and the liquid will remain at precisely 0 degrees Celsius (273 K) for the duration of the phase change.</span>
6 0
2 years ago
How many liters of 3.0 M NaOH solution will react with 2.4 mol H2SO4? (Remember to balance the equation.)
timurjin [86]

Answer:

1.6 L is the volume of NaOH that has reacted

Explanation:

The balanced reaction is:

H₂SO₄ + 2NaOH → Na₂SO₄  + 2H₂O

This is a neutralization reaction between a strong acid and a strong base. The products are the correspond salt and water.

We propose this rule of three:

1 mol of sulfuric acid needs 2 mol of NaOH to react to react

Then, 2.4 moles of H₂SO₄  will react with (2.4 . 2) / 1 = 4.8 moles of NaOH

As molarity is 3M, we can determine the volume of our solution

Molarity (M) = mol / volume(L) → Volume(L) = mol / Molarity

Volume(L) = 4.8 mol / 3 M = 1.6 L

3 0
2 years ago
A sample weighing 30.0 grams contains 1.5g of salt/ determine the percent salt found in the sample
jeka57 [31]
<span>Percentage by mass is the amount in mass of a component in a mixture per 100 unit of mass of the total mixture. Percentage by mass is the same as  %w/w. We can determine this by dividing the mass of the solute with the total mass of the mixture. We calculate as follows:

Percent salt = 1.5 g salt / 30.0 g x 100 = 5%  </span>
7 0
2 years ago
7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa?
suter [353]
<h3>Answer:</h3>

              0.8133 mol

<h3>Solution:</h3>

Data Given:

                 Moles  =  n  =  ??

                 Temperature  =  T  =  25 °C + 273.15  =  298.15 K

                  Pressure  =  P  =  96.8 kPa  =  0.955 atm

                  Volume  =  V  =  20.0 L

Formula Used:

Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

                  P V  =  n R T

where;  R  =  Universal Gas Constant  =  0.082057 atm.L.mol⁻¹.K⁻¹

Solving Equation for n,

                  n  =  P V / R T

Putting Values,

                  n  =  (0.955 atm × 20.0 L) ÷ (0.082057 atm.L.mol⁻¹.K⁻¹ × 298.15 K)

                 n  =  0.8133 mol

4 0
2 years ago
Read 2 more answers
Other questions:
  • Which is an example of practical pursuit of alchemy
    14·2 answers
  • Draw the electron dot structures for each molecule. Identify polar covalent bonds by assigning slightly positive and slightly ne
    13·1 answer
  • Write a complete step-by-step plan for dealing with broken glassware on the floor or lab table. Write your plan in list form in
    14·2 answers
  • What is the volume in mL of a 1.11 carat diamond, given the density of diamond is 3.51 g/mL? (1 carat = 200 mg). Use significant
    15·1 answer
  • HELP!!!!!!! How many moles of AgNO3 must react to form 0.854 mol Ag?<br> mol AgNO3
    12·2 answers
  • The enthalpy change for converting 1.00 mol of ice at -25.0 ∘c to water at 90.0∘c is ________ kj. the specific heats of ice, wat
    7·1 answer
  • A 1.803 g sample of gypsum, a hydrated salt of calcium sulfate, CaSO4 is heated at a temperature greater than 170 degree Celsius
    10·1 answer
  • You mix 500.0 mL of 0.250 M iron(III) chloride solution with 425.0 mL of 0.350 M barium chloride solution. Assuming the volumes
    13·1 answer
  • Based on the bond energies for the reaction below, what is the enthalpy of the reaction?HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O
    14·1 answer
  • This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!