The combustion of 0.374 kg of methane in the presence of excess oxygen produces 0.983 kg of carbon dioxide. What is the percent
1 answer:
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Answer:
the value of molar absorptivity is 229000
Explanation:
given data
phenol phthalein solution = 0.050 g
total volume = 100.0 ml
dilute = 100.0 ml
diluted sample = 0.18
solution
we get here concentration that is express as
concentration = ( mass of solute × 1000 ) ÷ ( molar mass of solute × volume of solution ) .............1
put here value
concentration =
concentration = 0.00157 M
and here dillution equation is express as
c1 × v1 = c2 × v2 .................2
here c1 and c2 is initial and final concentration
and v1 and v2 is initial and final volume
put here value
0.001571 × 0.050 = c2 × 100
c2 = 7.855 × M
and
now we get molar by absorbance equation that is
A = E × C × l ................3
here A is absorbance and E is molar and c is absorptivity and l is path length
put here value
0.18 = E × 7.855 × × 1
E = 229000
<h2>The answers are 
and 
</h2>
Explanation:
Given -
a) The molecular formula of ethylene glycol -
∴ The empirical formula of ethylene glycol will be -
Given -
b) The molecular formula of per-oxo-disulfuric acid (a compound used in bleaching agents) -
∴ The empirical formula of per-oxo-disulfuric acid will be -
Hence, the answers are and
.