Question

Give brainliest answer Nadal invests $5,678 at an annual interest rate of 4.5 percent for 6 years. For which variable can Nadal substitute the value 5,678 in the simple interest formula?i-prt A.I B.p C.r D.t

Answer 1

5678(1+(0.045×6))
5678=P as it is the principal amount

Answer 2

Answer:

B. p

Step-by-step explanation:

Since, the simple interest is,

$I=p\times r\times t$

Where, p is the invested or principal amount,

r is the annual rate of interest ( In decimal ),

t is the time ( In years ),

It is given,

$5,678 is invested at an annual interest rate of 4.5 percent for 6 years.

⇒ p = 5678, r = 4.5 % = 0.045 and t = 6,

Hence, he can substitute p for the value 5,678 in the simple interest formula.